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yaroslaw [1]
3 years ago
14

1.Maura had a pizza delivered to her home. The total amount she paid was $17.53. Included in the total amount were the menu pric

e of the pizza, 6% sales tax on the price of the pizza, and a $3.75 delivery fee.
What was the menu price of the pizza?

2. At a car wash, Lily paid $11.75 for the wash, 8% sales tax on the price of the wash, and $2 for the tip. Which statements are true? Choose exactly two answers that are correct. A. The equation that represents the total price, w, of the car wash is w + 0.08w + 2 = 11.75. B. The equation that represents the total price, w, of the car wash is 11.75 + 0.08(11.75) + 2 = w. C. The total cost of the car wash is $9.03. D. The total cost of the car wash is $14.69
Mathematics
1 answer:
Ierofanga [76]3 years ago
4 0
The menu price of the pizza would be 12.95. 
The total cost of the car wash is 14.69 and the equation is A.
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Simplify the expression: (19^1/9)^9
andrey2020 [161]
(19^1/9)^9=

19^1/9•9=

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Answer: Cylinder 1 - 25.1327412283 cubic cm
Cylinder 2 - 100.5309469149 cubic cm
Cylinder 3 - 226.1946710585 cubic cm

For each of the cylinders, we will need to use the same formula, h(pi(r squared)).

Cylinder 1 - 8(pi(1 squared)). 1 squared = 1. pi × 1 = 3.1415926536. 3.1415926536 × 8 = 25.1327412283 cubic cm.

Cylinder 2 - 8(pi(2 squared)). 2 squared = 4. 4 × pi = 12.5663706144. 12.5663706144 × 8 = 100.5309469149 cubic cm.

Cylinder 3 - 8(pi(3 squared)). 3 squared = 9. 9 × pi = 28.2743338823. 28.2743338823 × 8 = 226.1946710585 cubic cm.

- Hope it helps!



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According to the Rational Root Theorem, what are all the potential rational roots of f(x) = 5x3 – 7x + 11?
iogann1982 [59]

ANSWER

\pm1,\pm11,\pm \frac{1}{5} \pm \frac{11}{5}

EXPLANATION

The given function is;

f(x) = 5 {x}^{2}  - 7x + 11

The constant term is 11.

The coefficient of the leading term is 5.

The factors of 11 are ±1,±11

The factors of 5 are ±1,±5

According to the Rational roots Theorem,

the potential roots are obtained by expressing the factors of the constant term over the coefficient of the leading term.

\pm1,\pm11,\pm \frac{1}{5} \pm \frac{11}{5}

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