The speed of one bicyclist was 14.5mph, speed of the other bicyclist was 17.5mph.
Let the speed of one bicyclist=x mph
Let the speed of the other bicyclist=(x+3) mph
Hence:
Speed of one bicyclist:
3x+3(x+3)+2=98
3x+3x+9+2=98
6x=87
Divide both side by 6x
x=87/6
x=14.5 mph
Speed of the other bicyclist:
x+3 mph
14.5 mph+3 mph
=17.5 mph
Inconclusion the speed of one bicyclist was 14.5mph, speed of the other bicyclist was 17.5mph.
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A student can take three subjects in 40 ways.
<u>SOLUTION:</u>
Given that, there are 4 different math courses, 5 different science courses, and 2 different history courses.
A student must take one of each, how many different ways can this be done?
Now, number ways to take math course = 4
Number of ways to take science course = 5
Number of ways to take history course = 2
So, now, total possible ways = product of possible ways for each course = 4 x 5 x 2 = 40 ways.
Hence, a student can take three subjects in 40 ways.
Answer:
Step-by-step explanation:
x^2 + 17x + 60
(x + 12)(x + 5)
Y = -5x + 1
x = 1 , y = -4
x = 2 , y = -9
x = 3 , y = -14
so the answers are
(1,-4)
(2,-9)
(3,-14)
Answer: The answer is C on edg.
Step-by-step explanation: I got it right