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Margarita [4]
3 years ago
10

How many of the numbers from 10 through 96 have the sum of their digits equal to a perfect​ square?

Mathematics
1 answer:
vfiekz [6]3 years ago
5 0
8+9=17, 1+0=1. So, your biggest perfect square is 4, and the smallest one is 1.


So, one number is: 1+0=1=1^2


1+3=3+1=4+0=2+2=2^2. So, 4 more numbers: 13, 31, 40 and 22. (5 so far).


9+0=1+8=2+7=3+6=4+5=3^2
        |------------------------|
There four numbers are "symmetric", so you have also 81, 27, 36, and 45, to add up to 9. So, those that add up to 9, there are 9 of them. (14 so far)


7+9=8+8=16=4^2, so two more. (Note: 97 is not in there ...)

Overall you have 16 numbers.
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