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3 years ago

Segment addition, how do u solve it? Step by step.

Mathematics

1 answer:

weeeeeb [17]3 years ago

5 0

Answer:

x=7 DO=25 OG=35

Step-by-step explanation:

4x-3+2x+21=60 4(7)-3 2(7)+21

4x+2x -3+21 28-3=25 14+21=35

6x+18=60 DO=25 OG=35

60-18=42

6x=42

42/6=7

x=7

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The answer and to understand

antoniya [11.8K]

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3 years ago

Read 2 more answers

Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.

adoni [48]

Answer: The required derivative is $\dfrac{8x^2+18x+9}{x(2x+3)^2}$

Step-by-step explanation:

Since we have given that

$y=\ln[x(2x+3)^2]$

Differentiating log function w.r.t. x, we get that

$\dfrac{dy}{dx}=\dfrac{1}{[x(2x+3)^2]}\times [x'(2x+3)^2+(2x+3)^2'x]\\\\\dfrac{dy}{dx}=\dfrac{1}{[x(2x+3)^2]}\times [(2x+3)^2+2x(2x+3)]\\\\\dfrac{dy}{dx}=\dfrac{4x^2+9+12x+4x^2+6x}{x(2x+3)^2}\\\\\dfrac{dy}{dx}=\dfrac{8x^2+18x+9}{x(2x+3)^2}$

Hence, the required derivative is $\dfrac{8x^2+18x+9}{x(2x+3)^2}$

3 0

3 years ago

I want the answer of this . .

inessss [21]

Answer:

I believe it is 2 so X=2

5 0

3 years ago

H=4(x+3y)+2 make x the subject

blagie [28]

H = 4(x + 3y) + 2
H = 4x + 12y + 2
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5 0

2 years ago

Read 2 more answers

Choose the correct simplification of the expression (2ab5)3. (1 point) Question 8 options: 1) 8ab15 2) 8a3b8 3) 5a3b15 4) 8a3b15

d1i1m1o1n [39]

Answer:

4). $8a^{3}b^{15}$

Step-by-step explanation:

The Given expression is that,

$(2ab^{5})^{3}$

On simplifying,

$(2ab^{5})^{3}$ = $(2ab^{5} )(2ab^{5}) (2ab^{5})$

= $(2^{3} ) * (ab^{5})^{3}$

= (2×2×2) × ( $ab^{5}$ × $ab^{5}$ × $ab^{5}$ )

= $8a^{3}b^{15}$

Thus, <u>option 4</u> i.e. $8a^{3}b^{15}$ is the correct simplification of the given expression.

4 0

2 years ago