In the question, continuously should be annually.
Solution:
Applicable formula is;
A = P(1+r)^n
Where;
A = Total amount after 30 years = $9,110
P = Amount invested = $5,000
r = Annual interest rate in decimals
n = Number of years = 30
Substituting;
9110 = 5000(1+r)^30
9110/5000 = (1+r)^30
1.822 = (1+r)^30
Taking natural logs on both sides;
ln (1.822) = 30 ln (1+r)
0.5999 = 30 ln (1+r)
0.5999/30 = ln (1+r)
0.019998 = ln (1+r)
Taking exponents on both sides
e^0.019998 = 1+r
1.0202 = 1+r
r = 1.0202 -1 = 0.0202 =2.02%
Therefore, annual interest rate should be 2.02%.
Answer:
Using an excel spreadsheet I prepared an amortization schedule. For the 61st payment, the interest rate is increased from 0.5% to 0.625% monthly.
(a) Calculate the loan balance immediately after the 84th payment.
(b) Calculate the amount of interest in the 84th payment.
(c) Calculate the amount of the balloon payment.
As you can see, the interest amount for the 61st payment increases, while it had been decreasing previously.
Answer:
c. you need a lot of money to buy a home
Explanation:
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Answer:
申し訳ありませんが、私はできないので助けられません:-(
Explanation:
