The answer is 3.9. In fraction form the answer is 89/10. In mixed fraction form the answer is 8 9/10
SOLUTION
We want to find the area of the circle in the picture given.
We have been given the formula as
![\begin{gathered} A=\pi r^2 \\ We\text{ are told to take }\pi\text{ as 3} \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20A%3D%5Cpi%20r%5E2%20%5C%5C%20We%5Ctext%7B%20are%20told%20to%20take%20%7D%5Cpi%5Ctext%7B%20as%203%7D%20%5C%5C%20%20%5Cend%7Bgathered%7D)
From the circle, the radius r = 11 in.
The area of the circle becomes
![\begin{gathered} A=\pi r^2 \\ A=\pi\times r^2 \\ A=3\times11^2 \\ A=3\times11\times11 \\ A=363in^2 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20A%3D%5Cpi%20r%5E2%20%5C%5C%20A%3D%5Cpi%5Ctimes%20r%5E2%20%5C%5C%20A%3D3%5Ctimes11%5E2%20%5C%5C%20A%3D3%5Ctimes11%5Ctimes11%20%5C%5C%20A%3D363in%5E2%20%5Cend%7Bgathered%7D)
Hence the answer is 363 square-inches
C because you have a lot to say I don’t like you I ain’t talking to me I
I'm unsure of the question but this expression can be written as:
16 + x < 32.
This can be simplified to:
x < 16
Answer:
X= 8
Y= 130
(8, 130)
Step-by-step explanation:
I used a graphing calculator to see where the two equations intersected.
Hope this helped :)