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Dimas [21]
3 years ago
10

Verify that quadrilateral BCDE is a rhombus with vertices B(-5, 1), C(0, 6), D(5, 1) and E (0, -4) by showing that all four side

s are equal.
Mathematics
1 answer:
garri49 [273]3 years ago
4 0
Find the distance between each

between points (x1,y1) and (x2,y2)
D=\sqrt{(x2-x1)^2+(y2-y1)^2}



find and verify that
BC=CD=DE=EB

so
BC=\sqrt{(0-(-5))^2+(6-1)^2}=5√2
CD=\sqrt{(5-0)^2+(1-6)^2}=5√2
DE=\sqrt{(-4-1)^2+(0-5)^2}=5√2
EB=\sqrt{(-5-0)^2+(1-(-4))^2}=5√2

true
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