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Korolek [52]
4 years ago
13

How many different triangles can be constructed with side lengths 5 inches, 7inches, and 15 inches?

Mathematics
1 answer:
Kruka [31]4 years ago
8 0
The correct answer is exactly one triangle
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A square has vertices at the points A(-4,-4), B(-5,-4), C(-5,-3), and D(-4,-3). What is the area of this square? A. 1 square uni
laiz [17]

Answer:

Step-by-step explanation:

The length of AB = 1 unit.

area of square = 1² unit² = 1 square unit.

8 0
3 years ago
Using specific data, we find a significant difference in the proportion of fruit flies surviving after 13 days between those eat
pshichka [43]

Answer:

Test statistic:

z = (0.67 - 0.63) / 0.033 = 1.21

p - Value = P(z > 1.21) = 0.106

My conclusion: Fail to reject null hypothesis

No, there is no evidence of a difference

3 0
3 years ago
If the measure of angle 1 is (3 x minus 4) degrees and the measure of angle 2 is (4 x + 10) degrees, what is the measure of angl
arlik [135]

Answer:

58 degrees

Step-by-step explanation:

If angle 1 + angle 2 = 90 degrees, then:

(3x - 4) + (4x+10) = 90

Combine like terms:

(3x+4x) + (10-4) = 90

7x + 6 = 90

Subtract 6 from both sides:

7x = 84

Divide both sides by 7:

x = 12

**Plug x back into angle 2 (This step is easy to forget!):

angle 2 = 4(12) + 10

angle 2 = 48 + 10

angle 2 = 58 degrees

4 0
3 years ago
19. Given that angle BFC = 58°. Angle BXG = 48° and angle CBF 22 Find () 2BGX (iv) BCG (i) 2BGF (iv) ZBFG (ii) BCF H EE 58 48° D
RoseWind [281]

The unknown angles in the cyclic quadrilateral is as follows:

∠BGX = 74° (sum of angles in a triangle)

∠BGF = 180° (opposite angles of cyclic quadrilateral are supplementary)

∠BCF = 100°(sum of angles in a triangle)

∠BCG  = 26°

∠BFG = 22°

<h3>Cyclic Quadrilateral</h3>

A cyclic quadrilateral has all its angles equal to 360 degrees. The sum of angles in a cyclic quadrilateral is equals to 360 degrees.

Let's find the missing angles as follows:

∠BGX = 180 - 48 - 58 = 74° (sum of angles in a triangle)

∠BGF = 180 - 100 = 80° (opposite angles of cyclic quadrilateral are supplementary)

∠BCF = 180 - 22 - 58 = 100°(sum of angles in a triangle)

∠BCG = 100 - 74 = 26°

∠BFG ≅ CBF = 22°(alternate angles)

learn more on angles here: brainly.com/question/19430381

6 0
2 years ago
7-4????????????????????
polet [3.4K]

Answer:

3

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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