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DedPeter [7]
3 years ago
8

Let c be parametrized by x = et sin (10t) and y = et cos (10t) for 0 ≤ t ≤ 2. find the length l of

Mathematics
1 answer:
marysya [2.9K]3 years ago
7 0
C:x(t)=e^t\sin10t;\,y(t)=e^t\cos10t;\,0\le t\le2

\displaystyle\int_0^2\sqrt{x'(t)^2+y'(t)^2}\,\mathrm dt
\displaystyle=\int_0^2\sqrt{(e^t\sin10t+10e^t\cos10t)^2+(e^t\cos10t-10e^t\sin10t)^2}\,\mathrm dt
\displaystyle=\int_0^2e^t\sqrt{\sin^210t+20\sin10t\cos10t+100\cos^210t+\cos^210t-20\sin10t\cos10t+100\sin^210t}\,\mathrm dt
=\displaystyle\int_0^2e^t\sqrt{1+100}\,\mathrm dt
=\displaystyle\sqrt{101}(e^2-1)
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Alik [6]

Answer:

9) v= -12  

10) n= -7

Step-by-step explanation:

9) v - 15 = -27

Add 15 from both sides

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v = -12

10) n + 16 = 9

Subtract 16 from both sides

i.e. n + 16 - 16 = 9 - 16

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Hope this helps!!!

5 0
3 years ago
A water tank already contained 24 gallons of water before a pump was switched to fill it. The pump started at 10:00 am and by 10
grigory [225]

Answer:

The equation to represent  the amount of water that the tank contains (W) after the pump was working for T hours can be given as:

W=32T+24

Step-by-step explanation:

Given:

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The pump to fill the tank was switched to fill it.

From 10:00 AM to 10:30 AM the tank contained 40 gallons of water.

By 1:00 PM the tank contained 120 gallons of water.

To write an equation  which will tell the amount of water that the tank contains (W) after the pump was working for T hours

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Thus, in half an hour the pump filled = 40-24 = 16 gallons

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This confirms the data given for 1:00 PM.

This shows that the rate at  which the pump fills the tank is 32 gallons of water per hour.

The equation to represent  the amount of water that the tank contains (W) after the pump was working for T hours can be given as:

W=32T+24

4 0
3 years ago
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hi <3

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Step-by-step explanation:

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3 years ago
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