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nikdorinn [45]
3 years ago
12

Which has the larger area, a square with sides that are x +1 units long or a rectangle with a length of x +2 units and a width o

f x units?
A. Square
B. Rectangle
Mathematics
1 answer:
swat323 years ago
6 0

Answer:

A. Square

Explanation:

The square with sides: x+1

Has an area of: (x+1)^2

The rectangle with sides: x+2 and x

Has an area of: x(x+2)

So we simplify the square: (x+1).(x+1)= x^2+2x+1

Simplifying the rectangle: x^2+2x

Therefore the square area is larger by one unit.

Hope you get it!

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If the area of a rectangle with width x can be represented with the expression A(x) = x(14 – x), what is the perimeter of the re
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5 0
2 years ago
Among all rectangles that have a perimeter of 182, find the dimensions of the one whose area is largest.
Evgen [1.6K]

Answer:

<em>The largest rectangle of perimeter 182 is a square of side 45.5</em>

Step-by-step explanation:

<u>Maximization Using Derivatives</u>

The procedure consists in finding an appropriate function that depends on only one variable. Then, the first derivative of the function will be found, equated to 0 and find the maximum or minimum values.

Suppose we have a rectangle of dimensions x and y. The area of that rectangle is:

A=x.y

And the perimeter is

P=2x+2y

We know the perimeter is 182, thus

2x+2y=182

Simplifying

x+y=91

Solving for y

y=91-x

The area is

A=x.(91-x)=91x-x^2

Taking the derivative:

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Equating to 0

91-2x=0

Solving

x=91/2=45.5

Finding y

y=91-x=45.5

The largest rectangle of perimeter 182 is a square of side 45.5

6 0
3 years ago
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