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Viktor [21]
1 year ago
7

find the cost of carpeting the following rectangular rooms:a. Dimensions: 7.5m x 4.5m; Cost= $14.17/m^2b. Dimensions: 17 yd. x 1

2 yd; Cost= $25/yd^2
Mathematics
1 answer:
Bezzdna [24]1 year ago
6 0

a)

Dimensions: 7.5m x 4.5m

Cost , x= $14.17/m^2.

The area of the rectangular room can be calculated as,

\begin{gathered} A=7.5\times4.5 \\ =33.75m^2 \end{gathered}

Now, the cost of carpeting the rectangular room is,

\begin{gathered} C=xA \\ =14.17\times33.75 \\ =478.24\text{ } \end{gathered}

Therefore, the cost of carpeting the room with dimensions 7.5m x 4.5m is $478.24.

b)

Dimensions: 17 yd. x 12 yd.

Cost, x= $25/yd^2.

The area of the rectangular room can be calculated as,

\begin{gathered} A=17\times12 \\ =204yd^2 \end{gathered}

Now, the cost of carpeting the rectangular room is,

\begin{gathered} C=xA \\ =25\times204 \\ =5100 \end{gathered}

Therefore, the cost of carpeting the room with dimensions 17 yd. x 12 yd is $5100.

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RideAnS [48]

Answer:

41/45

Step by Step Explanation:

Add: 8/

10

+ 1/

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= 8 · 9/

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+ 1 · 10/

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= 72/

90

+ 10/

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= 72 + 10/

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= 82/

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= 2 · 41/

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= 41/

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For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(10, 9) = 90. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 10 × 9 = 90. In the following intermediate step, cancel by a common factor of 2 gives 41/

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.

In other words - eight tenths plus one ninth = forty-one forty-fifths.

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Answer:

3m - 2(m - 3) = 1 \\ 3m - 2m - 6 = 1 \\ m - 6 = 1 \\ m = 1 + 6 \\ m = 7

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Please help please thanks
alexandr402 [8]
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Θ lies in Quadrant II . sinθ=47sinθ=47 What is the exact value of cosθ in simplified form?
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I am assuming you mean 4/7 as the sine or cosine cannot be higher than 1.

Lets find <span>θ,
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θ = [sin-1](4/7) = 34.85 °

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