3 years ago

FOR BRAINLIEST PLEASE HELP

Mathematics

1 answer:

Andrews [41]3 years ago

3 0

B because u got to multiply

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18h

Step-by-step explanation:

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3 years ago

Suppose that a function f(x) is defined for all real values of x except at xequals=c. can anything be said about the existence

Margaret [11]

we are given that

f(x) is defined for all values of x except at x=c

Limit may or may not exist

case-1:

If there is hole at x=c , then limit exist

case-2:

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Examples:

case-1:

$\lim_{x \to c} \frac{x^2-cx}{(x-c)}$

We can simplify it

$\lim_{x \to c} \frac{x(x-c)}{(x-c)}$

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case-2:

$\lim_{x \to c} \frac{1}{(x-c)}$

Left limit is

$\lim_{x \to c-} \frac{1}{(x-c)}$

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Right Limit is

$\lim_{x \to c+} \frac{1}{(x-c)}$

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so, we can see that left limit is not equal to right limit

so, limit does not exist

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3 years ago

Let u = <-5, 2>, v = <-2, 6>. Find 4u + 3v.

Arisa [49]

Answer:<-26, 26>

Step-by-step explanation: <4(-5), 4(2)> and

<3(-2), 3(6)>

<-20, 8> and <-6, 18>

Now add <(-20+(-6)), (8+18)>

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3 years ago

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First one answer is C.
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-------------
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answer
A. 5.4919
--------------------
next step
x - 1 = 3x+9
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x = -5

answer
D. x - 1 = 3x+9

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3 years ago

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Mademuasel [1]

Answer:

it would take 4 days

Step-by-step explanation:BRAINLIEST PLEASE

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3 years ago