3 years ago

Parallelogram JKLM is shown on the coordinate plane below:

Mathematics

1 answer:

Bogdan [553]3 years ago

6 0

Answer:

B. K'(−6, −4); L'(−3, −3)

Step-by-step explanation:

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7 0

3 years ago

What is the area of major sector DFE?

melomori [17]

Answer:

B. 171.74 cm²

Step-by-step explanation:

Area of a sector = $\frac{\theta}{360} \times \pi r^2$ .

Where,

$\theta = 260$

radius (r) = 8.7 cm

Plug in the values into the formula

Area of sector = $\frac{260}{360} \times \pi 8.7^2$

Area of sector = $\frac{260 \times \pi 75.69}{360}$

Area of sector = 171.74 cm² (approximated)

6 0

3 years ago

Number 7. Please asap.

love history [14]

7a)

$\frac{n(n - 3)}{2} = 665\\n(n - 3) = 665 \cdot 2\\n(n - 3) = 1330\\n^2 - 3n = 1330\\n^2 - 3n - 1330 = 0\\n = \frac{-(-3) \pm \sqrt{(-3)^2 - 4 \cdot 1 \cdot (-1330)}}{2 \cdot 1} = \frac{3 \pm \sqrt{9 + 5320}}{2} = \frac{3 \pm \sqrt{5329}}{2} = \frac{3 \pm 73}{2}\\n_1 = \frac{3 + 73}{2} = \frac{76}{2} = 38\\n_2 = \frac{3 - 73}{2} = \frac{-70}{2} = -35$