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3 years ago

Pleeeaaasssee Help!!!!

Mathematics

2 answers:

jarptica [38.1K]3 years ago

8 0

It’s the first one!! :)))

USPshnik [31]3 years ago

8 0

i agree it is the first option on the question.

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Pls help with stats

aleksklad [387]

Answers:

Exactly 25%
median = 450
Not enough info (see below)
IQR = 24
IQR = 192

=========================================================

Explanations:

By definition, the quartiles split the data into four equal parts. The first quartile (Q1) will have 25% of the data below it.
The second quartile is the exact same value as the median. This is because the median splits the data into two equal halves, i.e. is at the midpoint.
There's not enough info. We can determine that 25% of the company makes more than $60,000, but we don't know how many people total work at the company. This info is missing.
Subtract the third and first quartiles (Q3 and Q1) to get the interquartile range (IQR). So IQR = Q3 - Q1 = 45-21 = 24
Same idea as the previous problem. IQR = Q3 - Q1 = 316.5 - 124.5 = 192

3 0

3 years ago

If f(1) = 10 and f(n) = f(n = 1) – 4 then find the value of f(5).

svetoff [14.1K]

Given:

$f(1)=10$ and $f(n)=f(n-1)-4$ .

To find:

The value of f(5).

Solution:

We have,

$f(n)=f(n-1)-4$

For $n=2$ ,

$f(2)=f(2-1)-4$

$f(2)=f(1)-4$

$f(2)=10-4$

$f(2)=6$

For $n=3$ ,

$f(3)=f(3-1)-4$

$f(3)=f(2)-4$

$f(3)=6-4$

$f(3)=2$

For $n=4$ ,

$f(4)=f(4-1)-4$

$f(4)=f(3)-4$

$f(4)=2-4$

$f(4)=-2$

For $n=5$ ,

$f(5)=f(5-1)-4$

$f(5)=f(4)-4$

$f(5)=-2-4$

$f(5)=-6$

Therefore, the value of $f(5)$ is $-6$ .

5 0

3 years ago

PLEASE HELP <br> it hasn’t been a good day and i don’t feel like doing this

Diano4ka-milaya [45]

Answer:

Both are quadrant

Step-by-step explanation:

4 0

3 years ago

Find the volume of the composite figure

aniked [119]

One of the numbers are cut off but I figured it out with what I had:11 cu in

5 0

3 years ago

A weather forecast states that there is a 20% probability of rain in the next three days. Describe a simulation you could perfor

iVinArrow [24]

Answer:

my hands hurt, pls give brainilist and hope this helps

Step-by-step explanation:

Before leaving for work, Victor checks the weather report in order to decide whether to carry an umbrella. The forecast is “rain" with probability 20% and “no rain" with probability 80%. If the forecast is “rain", the probability of actually having rain on that day is 80%. On the other hand, if the forecast is “no rain", the probability of actually raining is 10%.

1. One day, Victor missed the forecast and it rained. What is the probability that the forecast was “rain"?

2. Victor misses the morning forecast with probability 0.2 on any day in the year. If he misses the forecast, Victor will flip a fair coin to decide whether to carry an umbrella. (We assume that the result of the coin flip is independent from the forecast and the weather.) On any day he sees the forecast, if it says “rain" he will always carry an umbrella, and if it says “no rain" he will not carry an umbrella. Let U be the event that “Victor is carrying an umbrella", and let N be the event that the forecast is “no rain". Are events U and N independent?

3. Victor is carrying an umbrella and it is not raining. What is the probability that he saw the forecast?

3 0

3 years ago