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ivann1987 [24]
2 years ago
14

What fraction is equivalent to -2/3

Mathematics
1 answer:
slega [8]2 years ago
3 0
-4/6
-8/12
-16/24
etc.

there are infinitely may equivalent of this fraction,

multipliy the numerator and denominator both qith the same number and you'll gey your answer.

as I did in

-4/6 = (-2/3) ×(2/2)
-8/12= (-2/3) × (4/4)
-16/24= (-2/3) × (8/8)


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What is the inverse of the given relation?<br> y=3x+12
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We are asked in the problem to determine the inverse of the relation y = 3x + 12. first step is to express the equation in terms of y, that is y -12 = 3x, then exchange the places of x and y, that is x - 12 = 3y. This is the final answer
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Kami has 7 liters of water to fill water bottles that each hold 2.8 liters. How many bottles can she fill?
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ASAP Quadrilateral ABCD is similiar to quadrilateral EFGH. The lengths of the three longest sides in quadrilateral ABCD are 24 f
Nitella [24]

Answer:

D. 6 feet.

Step-by-step explanation:

The third longest side of ABCD is 12 feet long and the third longest side of EFGH is 18 feet long.

As they are similar the corresponding sides are in the same ratio so

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3 0
3 years ago
WILL GIVE A BRAINLIEST PLEASE HELP!!
skelet666 [1.2K]
A= l*w
168= 14*w

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The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l
sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

A=\frac{\sqrt{3} }{4} x^2

(c)

A=\frac{3\sqrt{3} }{2} x^2

(d)

V=\frac{3\sqrt{3} }{2} x^3 units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

=\frac{\sqrt{3} }{4} b^2

h=3x

b=x

now, we can plug values

A=\frac{\sqrt{3} }{4} x^2

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

=6\times \frac{\sqrt{3} }{4} x^2

=\frac{3\sqrt{3} }{2} x^2

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)

V=\frac{3\sqrt{3} }{2} x^3 units^3


3 0
3 years ago
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