Answer:
<h3>The diameter is 4cm</h3>
Step-by-step explanation:
Volume of a sphere is

Where r is the radius
diameter = radius × 2
To find the diameter we must first find the radius
Volume = 34cm³
That's
![34 = \frac{4}{3} \pi {r}^{3} \\ \\ 34 \times 3 = 4\pi {r}^{3} \\ \\ 102 = 4\pi {r}^{3} \\ {r}^{3} = \frac{102}{4} \pi \\ \\ r = \sqrt[3]{ \frac{51}{2\pi}} \\ \\ r = 2.01 \\ \\ r = 2.0 cm](https://tex.z-dn.net/?f=34%20%3D%20%20%5Cfrac%7B4%7D%7B3%7D%20%5Cpi%20%7Br%7D%5E%7B3%7D%20%20%5C%5C%20%20%5C%5C%2034%20%5Ctimes%203%20%3D%204%5Cpi%20%7Br%7D%5E%7B3%7D%20%20%5C%5C%20%20%5C%5C%20102%20%3D%204%5Cpi%20%7Br%7D%5E%7B3%7D%20%20%5C%5C%20%20%7Br%7D%5E%7B3%7D%20%20%20%3D%20%5Cfrac%7B102%7D%7B4%7D%20%5Cpi%20%5C%5C%20%20%5C%5C%20r%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B51%7D%7B2%5Cpi%7D%7D%20%20%5C%5C%20%20%5C%5C%20r%20%3D%202.01%20%5C%5C%20%20%5C%5C%20r%20%3D%202.0%20cm)
Diameter = 2 × 2cm
<h3>= 4cm</h3>
Hope this helps you
Answer:
Step-by-step explanation:
Number of cows increased=60
Old quality of milk consumed=12.8litres
New Increase in milk consumed=15litres
Therefore the number of cows in the farm if the quality of milk is 1340litres=y
Therefore, 1cow =15litres
y cows= 1340litres
Crossmultiply:
15litres×ycows=1340litres
Make y the subject of formula
y= 1340÷15
y=89.33cows
Therefore,the number of cows on the farm if farmer gets 1340litres of milk would be 89cows.
Answer:
0.9332
Step-by-step explanation:
Answer:
The correct answer to the following question will be "280 units".
Step-by-step explanation:
The given values are:
Mean = 200
Standard deviation = 30
Let's ask that the supplier needs to reach 99.9% of the standard of operation. To reach this quality of operation, she has to preserve an inventory of
Now,
⇒ 
On putting the values, we get
⇒ 
⇒ 
⇒ 
290 units would then accomplish a level of service of 99.9%.
Half unpurchased units can indeed be purchased at $30000 i.e. no failure. If he requests 300, there will be losses on 5 products that are unsold.
Hence, ordering 280 units seems to be preferable