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Llana [10]
2 years ago
7

1.) Write an equation of the line that passes through the point (3,-2) and is

Mathematics
1 answer:
GarryVolchara [31]2 years ago
8 0

Answer:

y = 2x - 8

Step-by-step explanation:

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Maria solved the equation below and got x = –4. Which of the following choices verifies that her solution is correct? 5x + 22 =
VladimirAG [237]
5(-4)+22 = (-4)+6
-20+22 = -4+6
2 = 2
Maria is correct, since both sides equally match.
3 0
3 years ago
Read 2 more answers
A person weighing 170 lb burns 8.6 calories per minute while mowing a lawn. How many calories would be burned A person weighing
lord [1]

Answer:

4,644 calories

Step-by-step explanation:

The computation of the number of calories to be burned is shown below

r = rate = 8.6 cal/min

= 8.6 cal ÷ [(1 ÷ 60)hr]

= 516 cal/hr

Now

Calories consumed in 9 hours is

= (516 cal/hr) × (9 hrs)

= 4,644 calories

8 0
3 years ago
A.53 degrees <br> B.143 degrees <br> C.37 degrees <br> D.90 degrees <br> ???????????????????????????
vaieri [72.5K]

Answer:

C. 37° Opposite angles

I hope I helped you^_^

4 0
2 years ago
Which expression is equivalent to (4x^4/2x^3)^3?<br><br> A) 2x<br> B) 8x<br> C) 8x^3<br> D) 16x^21
allsm [11]

Answer:

None are you sure you have the right expressions.

Step-by-step explanation:

(4x^4/2x^3)^3=(2x^4*x^3)^3=(2x^7)^3=8x^21

5 0
3 years ago
How do you do this? Please give explanation
Komok [63]

Answer:

  2, 1, 3, 4, 6, 5

Step-by-step explanation:

The rate of change of function f(x) on an interval [a, b] is defined as ...

  average rate of change = (f(b) -f(a))/(b -a)

For the function h(x) = 2^-x, this will be ...

  arc = (h(b) -h(a))/(b -a) = (2^-b -2^-a)/(b-a) = (2^-a)(2^(a-b) -1)/(b -a)

__

1. For the interval [0, 2], the average rate of change is ...

  arc = (2^-0)(2^(0-2) -1)(2 -0) = (1/4 -1)/2 = -3/8 = -0.375

  1 goes in the 2nd answer blank

2-6. For the other intervals, it is convenient to let a calculator or spreadsheet compute the values. The average rates of change are shown in the attachment.

8 0
2 years ago
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