The Mean Value Theorem:
If a function is continuous on [ a, b ] and differentiable on ( a , b ) than there is a point c in ( a, b ) such that:
f ` ( c )= ( f ( b ) - f ( a ) ) / ( b - a )
f ` ( c ) = ( f ( 2 ) - f ( 0 ) ) / ( 2 - 0 )
f `( x ) = 10 x - 3
f ` ( c ) = 10 c - 3
2 f ` ( c ) = 16 - 2
f ` ( c ) = 7
7 = 10 c - 3
c = 1
Answer:
Yes, the function is continuous on [ 0, 2 ] and differentiable on ( 0, 2 ).
Answer: AB = 6
Step-by-step explanation:
If CD = 12 , AC also = 12
B is the midpoint of AC so one side = 6
AB is one side of AC , so AB = 6
I am not a professional, I am simply using prior knowledge!
Note- It would mean the world to me if you would mark me brainliest!
Answer:
Slope (m) = 3, y-intercept (b) = -1
Step-by-step explanation:
First, we need to write the equation in y = mx + b.
To do this, add 3x to both sides.
y = 3x - 1 is your result.
Now, we have everything we need to do determine our slope and y-intercept in just this equation alone.
Remember, m = slope and b = y-intercept.
In this equation:
m = 3
b = -1
So your slope is 3, and your y-intercept is -1
Answer:
8x^2+19x
Step-by-step explanation:
Simplify the expression by combining like terms. Terms which look a like and sound a like should be added together.
3x^2+7x+3+5x^2+12x
x^2 terms: 3x^2+5x^2=8x^2
x terms: 7x+12x=19x
constants: 3
Together is is 8x^2+19x+3.
