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Citrus2011 [14]
3 years ago
12

Last summer,at a camp,the ratio of the number of boy campers to girl campers is 9:6.If there is 225 campers,how many boy campers

were there?How many girl campers?
Mathematics
1 answer:
nalin [4]3 years ago
4 0

Answer: There were 135 boy campers and 90 girl campers.

Step-by-step explanation:

Let be "b" the number of boys campers and "g" the number of girl campers.

Given the following ratio of the number of boy campers to girl campers:

9:6

We know that for every 9 boys campers there were 6 girl camper; if we add them we get this sum:

9+6=15\ campers

Knowing that there were a total of  225 campers, we can set up the following proportion in order to find the value of "b". Then, solving for "b" we get:

\frac{9}{15}=\frac{b}{225}\\\\b=(225)(\frac{9}{15})\\\\b=135

Finally, we get that the number of girl campers was:

g=225-135=90

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Plzzzzzzzzz help <br> 20.41 rounded to the nearest hundredth
just olya [345]

Answer:

20.41

20=nearest whole number

20.4=nearest tenth

20.41=nearest hundredth

hope this helps

have a good day :)

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Historical data for a local steel manufacturing company shows that the average number of defects per standard sheet of steel is
Yanka [14]

Answer:

Therefore the correct answer is A.) 84.88%

Step-by-step explanation:

i) λ = 2

ii) λ for three units = 2 \times 3 = 6

iii) P(x ≥ 4) = 1 - P(x < 4) = 1 - {P(x = 0) + P(x = 1) + P(x = 2)  + P(x = 3) }

                                = 1 - { \frac{e^{-6}6^{0} }{ 0!} + \frac{e^{-6}6^{1} }{ 1!}  + \frac{e^{-6}6^{2} }{ 2!} + \frac{e^{-6}6^{3} }{ 3!}  }

                                = 1 - (0.0025 + 0.0149 + 0.0446 + 0.0892)

                                = 0.8488

 Therefore the correct answer is A.) 84.88%

 

8 0
2 years ago
Estimate the integral ∫6,0 x^2dx by the midpoint estimate, n = 6
Anettt [7]
Splitting up the interval [0, 6] into 6 subintervals means we have

[0,1]\cup[1,2]\cup[2,3]\cup\cdots\cup[5,6]

and the respective midpoints are \dfrac12,\dfrac32,\dfrac52,\ldots,\dfrac{11}2. We can write these sequentially as {x_i}^*=\dfrac{2i+1}2 where 0\le i\le5.

So the integral is approximately

\displaystyle\int_0^6x^2\,\mathrm dx\approx\sum_{i=0}^5({x_i}^*)^2\Delta x_i=\frac{6-0}6\sum_{i=0}^5({x_i}^*)^2=\sum_{i=0}^5\left(\frac{2i+1}2\right)^2

Recall that

\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6
\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2
\displaystyle\sum_{i=1}^n1=n

so our sum becomes

\displaystyle\sum_{i=0}^5\left(\frac{2i+1}2\right)^2=\sum_{i=0}^5\left(i^2+i+\frac14\right)
=\displaystyle\frac{5(6)(11)}6+\frac{5(6)}2+\frac54=\frac{143}2

8 0
2 years ago
A phone company offers to monthly plans. Plan a cost $23 plus an additional $.08 for each minute of calls. Plan B cost $19 an ad
Anettt [7]

Answer:

The indifference point is 100 minutes.

Step-by-step explanation:

Giving the following information:

Plan a cost $23 plus an additional $.08 for each minute of calls.

Plan B cost $19 an additional $.12 for each minute of calls.

<u>First, we need to establish the total cost formula for each plan:</u>

Plan A= 23 + 0.08*x

Plan B= 19 + 0.12*x

x= number of minutes

<u>Now, to calculate the indifference point, we equal both formulas and isolate x:</u>

23 + 0.08x = 19 + 0.12x

4 = 0.04x

100= x

The indifference point is 100 minutes.

<u>Prove:</u>

Plan A= 23 + 0.08*100= $31

Plan B= 19 + 0.12*100= $31

5 0
3 years ago
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Setler79 [48]

Answer:

a) 3

Step-by-step explanation:

3+10= 13

hope this helped :)

7 0
3 years ago
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