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3 years ago

A sphere and a cylinder have the same radius and height. The volume of the cylinder is 30 meters cubed

Mathematics

2 answers:

jekas [21]3 years ago

8 0

Answer:

sorry it's late but the answer should be 20 meters cubed

Step-by-step explanation:

Ne4ueva [31]3 years ago

3 0

Answer:

its B

Step-by-step explanation:

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At the end of a game, Fran had 14 points and Calvin had -22 points. How many points did Fran win? A: -36 B: 8 C: -8 D: 36

weqwewe [10]

Answer:

Step-by-step explanation:

Number of points Fran won = points Fran had - points Calvin had

14 - (-22)

= 14 + 22

= 36

4 0

3 years ago

Suppose a box contains 3 defective light bulbs and 12 good bulbs. Two bulbs are chosen separately from the box without replaceme

Flauer [41]

Answer:

$Probability = \frac{12}{35}$

Step-by-step explanation:

Given

Represent Defective Bulbs with D and non good bulbs with G

$D = 3$

$G = 12$

The probability that one is defective and the other is not can be represented with: (D and G) or (G and D)

Which means that the defective is selected first, then the good one or the good one is selected first, then the defective one.

This is then calculated as:

$Probability = \frac{n(D}{Total} * \frac{n(G)}{Total - 1} + \frac{n(G}{Total} * \frac{n(D)}{Total - 1}$

We used Total - 1 on second selections because it is a probability without replacement

$Probability = \frac{3}{15} * \frac{12}{15- 1} + \frac{12}{15} * \frac{3}{15- 1}$

$Probability = \frac{3}{15} * \frac{12}{14} + \frac{12}{15} * \frac{3}{14}$

$Probability = \frac{1}{5} * \frac{6}{7} + \frac{2}{5} * \frac{3}{7}$

$Probability = \frac{6}{35} + \frac{6}{35}$

$Probability = \frac{12}{35}$

7 0

3 years ago

Describe two methods for finding the sale price of an items that is discounted 30%

madam [21]

you could write an equation or make a table.

4 0

4 years ago

The table shows the maze-completion times, in seconds, of two sets of mice in an experiment.Which statement is true about the va

Yanka [14]

The value of $Q_{1} , Q_{2} ,$ , and $Q_{3}$ of each data is shown in the diagram below

Group A

Mean = $\frac{41+44+45+48+49+50+52+54+55+58}{10} =49.6$
Median = 49.5
Range = $58-41=17$
Interquartile Range = $Q_{3}- Q_{1} =54.5-44.5=10$

Group B
Mean = $\frac{40+41+43+45+48+52+55+57+60+62}{10}=50.3$
Median = 50
Range = 62-40=22
Interquartile range = 58.5-42 = 16.5

Correct statement: the time in Group B has a greater interquartile range