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leonid [27]
2 years ago
10

How do u work out 65% of 8700

Mathematics
1 answer:
vagabundo [1.1K]2 years ago
7 0

Step-by-step explanation:

please mark me as brainlest

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terry opened a savings account in December with $132 and saved $27 each month beginning in January the value of terrys account i
liq [111]
Let S be the amount in a savings account. 
Let m be the number of months.

General equation
S = 132 + 27m

Specific question
July is the 7th month of the year including both January and July.
S = 132 + 7*27
S = 132 + 189
S = 321

Reasonableness?
Good question. You could estimate an answer.
Start with 150 dollars and say that you add 25 a month.
7 * 25 = 175
S = 150 + 175 = 325 All of this was done in my head. Since the exact answer obtained using the formula is 321, I think that's pretty reasonable using my estimate is a guide.
4 0
3 years ago
Can someone please explain step by step on how I subtract fractions like for an a example!
kotykmax [81]

Keep the denominators the same and subtract the numerators. So for example in your example:

7/8 - 3/8

Leave the 8 alone. Subtract 3 from 7.

7 - 3 = 4

So answer is:

4/8

Sometimes they may have to simplify the answer, and in this case, 4/8 could be simplified to 1/2

3 0
2 years ago
Read 2 more answers
I NEED HELP ASP 20 points
leva [86]
Circumference
C = pi d
C = 3.14 x 10
C = 31.4 cm

Area
A = pi r^2
A = 3.14 x 5^2
A = 78.5 cm^2
8 0
2 years ago
Solve the proportion. Solve for w
deff fn [24]
The answer for w is w=3.5 <span />
6 0
2 years ago
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Please help!
larisa [96]
Answer: 
Choice A
1/17; no, they are dependent events

============================================

Explanation:

There are 13 spades and 52 cards total. So 13/52 = 1/4 is the probability of drawing one spade

If we do not replace the card we pull out, then the probability of another spade is 12/51 since there are 12 spades left out of 51 total. 

Multiply the fractions 1/4 and 12/51 to get
(1/4)*(12/51) = (1*12)/(4*51) = 12/204 = 1/17

The two events are not independent because the second event (pulling out a second spade) depends entirely on what happens in the first event (pulling out a first spade). The fact that the probability is altered indicates we have dependent events.

6 0
3 years ago
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