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3 years ago

Please show the work as well simplify -3.3+5.5

Mathematics

2 answers:

vampirchik [111]3 years ago

7 0

5.5+-3.3 is the same as 5.5-3.3 so
5.5
-3.3
——
2.2
5-3 = 2
5-3 = 2
(Bring decimal down)

Zigmanuir [339]3 years ago

3 0

Answer:

Therefore, 5.5-3.3=2.2

Step-by-step explanation:

I wrote on a piece of paper.

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Does the graph of the straight line with slope of -3 and y-intercept of -4 pass through the point (-2, 2)?

vodka [1.7K]

Answer:

abcdefghijklmnopqrstuvwxyz

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2 years ago

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Maya is showing her work in simplifying (5.2 − 4.5) − 5.5 + 4.8. Identify any error in her work or reasoning.

Dmitry_Shevchenko [17]

If putting 5.2 and 4.5 in fraction form, her error must have been timing 3 by 3 to 5.2 and 4.5 as a fraction. Meaning that 5.5 and 4.8 is wrong

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3 years ago

Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio

JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

$Initial =1\ million$

$6\ years\ later = 500,000$

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

$\frac{dA}{dt} = kA$

Where k represents the constant of proportionality

$\frac{dA}{dt} = kA$

Multiply both sides by dt/A

$\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}$

$\frac{dA}{A} = k\ dt$

Integrate both sides

$\int\ {\frac{dA}{A} = \int\ {k\ dt}$

$ln\ A = kt + lnC$

Make A, the subject

$A = Ce^{kt}$

$t = 0\ when\ A =1\ million$ i.e. At initial

So, we have:

$A = Ce^{kt}$

$1000000 = Ce^{k*0}$

$1000000 = Ce^{0}$

$1000000 = C*1$

$1000000 = C$

$C =1000000$

Substitute $C =1000000$ in $A = Ce^{kt}$

$A = 1000000e^{kt}$

To solve for k;

$6\ years\ later = 500,000$

i.e.

$t = 6\ A = 500000$

So:

$500000= 1000000e^{k*6}$

Divide both sides by 1000000

$0.5= e^{k*6}$

Take natural logarithm (ln) of both sides

$ln(0.5) = ln(e^{k*6})$

$ln(0.5) = k*6$

Solve for k

$k = \frac{ln(0.5)}{6}$

$k = \frac{-0.693}{6}$

$k = -0.1155$

Recall that:

$\frac{dA}{dt} = kA$

Where

$\frac{dA}{dt}$ = Rate

So, when

$A = 600000$

The rate is:

$\frac{dA}{dt} = -0.1155 * 600000$

$\frac{dA}{dt} = -69300$

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

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2 years ago

a beekeeper estimates that his bee population will triple each year. Currently he has 150 bees. Write a function to represent th

Soloha48 [4]

Answer:

Exponential functions!

Step-by-step explanation:

I think what you are dealing with is an exponential function!

So, to solve this, we need to first understand the main form of an exponential function:

$f(x)=a*b^{x}$

Where a is the number we start off with, and b is the constant thing(forgot what it was called).

Now, 150 is our starting number, so it is a, and b is our constant at which the initial term is multiplied, which is 3!

Also, defining variables:

Let f(x)= # of Bees

Let x= # of years

Thus, here is our equation:

$f(x)=150*3^{x}$

So, that's it!

Now, some of my answers have been recently deleted because they violated community guidelines for recommending something that shall not be named, so if you do really need help on the subject, look online! It is the largest source of information humanity has created! (also I cannot explain Exponential Functions in a single paragraph)

Stay Safe!

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2 years ago

-3(p-7) > 21 solve for p

Goryan [66]

Answer:

p < 0

Step-by-step explanation:

Given

- 3(p - 7) > 21

Divide both sides by - 3, reversing the symbol as a result of dividing by a negative quantity.

p - 7 < - 7 ( add 7 to both sides )

p < 0

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3 years ago