and 10.6 is already written as a decimal.
Strictly speaking, x^2 + 2x + 4 doesn't have solutions; if you want solutions, you must equate <span>x^2 + 2x + 4 to zero:
</span>x^2 + 2x + 4= 0. "Completing the square" seems to be the easiest way to go here:
rewrite x^2 + 2x + 4 as x^2 + 2x + 1^2 - 1^2 = -4, or
(x+1)^2 = -3
or x+1 =i*(plus or minus sqrt(3))
or x = -1 plus or minus i*sqrt(3)
This problem, like any other quadratic equation, has two roots. Note that the fourth possible answer constitutes one part of the two part solution found above.
Answer:
286
Step-by-step explanation:
Use term formula for +/-
Tn = a + (n-1)d
n= number of term
a= first number in sequence
d= difference between each number
T55 = 16 + (55-1)5
T55 = 16 + 270
=286
Answer:
3
Step-by-step explanation:
4*3=12
3*3=9
5*3=15
So you find the number that can be multiplied or divided by each side the same to get the new number
