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mojhsa [17]
3 years ago
13

Amanda can jog 18 miles in 5 hours. At this rate, how many miles can Amanda jog in 4 hours?

Mathematics
2 answers:
Afina-wow [57]3 years ago
6 0

we know that

Amanda can jog 18 miles in 5 hours

so

by proportion

Find the number of miles that Amanda  can jog in 4 hours

\frac{18}{5} \frac{miles}{hours} =\frac{x}{4} \frac{miles}{hours} \\ \\5*x=18*4 \\ \\x=72/5 \\ \\ x=14.4\ miles

therefore

<u>the answer is</u>

14.4\ miles

MaRussiya [10]3 years ago
4 0
18 = x
__ __
5 4
x = 18•4 / 5
72/5 = 14.4 final answer
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For this problem we can represent the situation as a rectangle triangle.
 x: depth of water.
 40: Base. "Antonio pulls the lily to one side, keeping the stem straight, until the blossom touches the water at a spot"
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 x ^ 2 + 40 ^ 2 = (x + 8) ^ 2
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6 0
3 years ago
Marco needs to buy some cat food. At the nearest​ store, 6 bags of cat food cost ​$28.50. How much would Marco spend on 5 bags o
olga55 [171]

Answer:

$23.75

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I need so much help!!!!
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<em>Answer:</em>

94.25m

<em>Explanation:</em>

\frac{3cm}{4.5m} × \frac{19.5}{x}

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3 years ago
Three times each day, a quality engineer samples a component from a recently manufactured batch and tests it. Each part is class
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Answer:

Step-by-step explanation:

Hello!

Three samples of components manufactured are taken per day. They are classified as:

D: "Conforming (suitable for its use)"

E: "Downgraded (unsuitable for the intended purpose but usable for another purpose)"

F: "Scrap (not usable)"

This classification includes the three events that may occur in your sample space S. The experiment consists in recording the categories of the three parts tested in a day.

a. List the 27 outcomes in the sample space.

The possible outcomes in the space sample are the combinations of the three events. To avoid using the same letters as in the following questions I've named the evets as D, E, and F

S={DDD, DED, DFD, DEF, DFE, DEE, DFF, DDE, DDF , EDE, EEE, EFE, EED, EEF, EDF, EFD, EDD, EFF , FDF, FEF, FFF, FFE, FFD, FDE, FED, FDD, FEE}

b. Let A be the event that all the parts fall into the same category. List the outcomes in A.

A: "All the parts fall into the same category"

You have three possible outcomes for this event, that the three compounds are conforming, "DDD", that the three are unconforming, "EEE", or that the three compounds are scrap, "FFF". There are only three possible outcomes for this event.

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B: "There is a part in each category"

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S={DEF, DFE, EDF, EFD, FDE, FED}

d. Let C be the event that at least two parts are conforming. List the outcomes in C.

C: "At least two parts are conforming"

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S={DDD, DED, DFD, DDE, DDF , EDD, FDD}

A total of 7 combinations fit this event.

I hope you have a SUPER day!

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