see the attached figure to better understand the problem
we know that
The Area of the composite figure is equal to the sum of Area 1, Area 2 and Area 3
The Area 1 is a triangle
The Area 2 is a rectangle
The Area 3 is equal a semicircle
therefore
<u>the answer is the option</u>
a triangle, a rectangle, and a semicircle
For this case you must simplify the expression respecting the rules of multiplication of mathematics.
The steps to simplify the expression are the following:
First multiply what is in the parentheses
-2x ^ 2 (x - 5) + x (2x ^ 2 - 10x) + x
-2x ^ 3 + 10x ^ 2 + 2x ^ 3 - 10x ^ 2 + x
Then add the terms that have the same exponent
(-2x ^ 3 + 2x ^ 3) + (10x ^ 2 - 10x ^ 2) + x
x
The final simplification is
x
answer
x
<h3>Answer:</h3>
- f(1) = 2
- No. The remainder was not 0.
<h3>Explanation:</h3>
Synthetic division is quick and not difficult to learn. The number in the upper left box is the value of x you're evaluating the function for (1). The remaining numbers across the top are the coefficients of the polynomial in decreasing order by power (the way they are written in standard form). The number at lower left is the same as the number immediately above it—the leading coefficient of the polynomial.
Each number in the middle row is the product of the x-value (the number at upper left) and the number in the bottom row just to its left. The number in the bottom row is the sum of the two numbers above it.
So, the number below -4 is the product of x (1) and 1 (the leading coefficient). That 1 is added to -4 to give -3 on the bottom row. Then that is multiplied by 1 (x, at upper left) and written in the next column of the middle row. This proceeds until you run out of numbers.
The last number, at lower right, is the "remainder", also the value of f(x). Here, it is 2 (not 0) for x=1, so f(1) = 2.
Given that a polynomial function P(x) has rational coefficients.
Two roots are already given which are i and 7+8i,
Now we have to find two additional roots of P(x)=0
Given roots i and 7+8i are complex roots and we know that complex roots always occur in conjugate pairs so that means conjugate of given roots will also be the roots.
conjugate of a+bi is given by a-bi
So using that logic, conjugate of i is i
also conjugate of 7+8i is 7-8i
Hence final answer for the remaining roots are (-i) and (7-8i).