F(x)= x^3-4x^2+9 and let g(x)=6x^3+x^2-5x-12 what is f(x)-g(x)

Mathematics

1 answer:

Anarel [89]2 years ago

7 0

$f(x) - g(x) = -5x^3-5x^2+5x +21$

Step-by-step explanation:

Given functions are:

$f(x) = x^3-4x^2+9\\g(x) = 6x^3+x^2-5x-12$

We have to find the difference of functions

So,

$f(x) - g(x) = x^3-4x^2+9 - (6x^3+x^2-5x-12)\\= x^3-4x^2+9-6x^3-x^2+5x+12$

Combining like terms

$x^3-4x^2+9-6x^3-x^2+5x+12\\=x^3-6x^3-4x^2-x^2+5x+9+12\\= -5x^3-5x^2+5x +21$

Hence,

$f(x) - g(x) = -5x^3-5x^2+5x +21$

Keywords: Functions, Operations

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