Answer:49 sec
Step-by-step explanation:
Given
Maximum speed to reach is 183.58 mi/h
Length of course is 5 mi
acceleration rate is defined by 60mi/h in 4 sec
therefore acceleration(a)


To reach a speed of 183.58mi/h with an acceleration of 
Using equation of motion
v=u+at


t=0.00339 hours
t=12.23 s reach maximum speed
To complete course it takes


t=0.01360 hour
or 
G=4ca-3ba <=> G=a(4c-3b)
<=> a=G/(4c-3b)
Answer:
P= 4a would be the answer
John wanted to go on a train. the equation y=9/5 x describes the number of miles y that a train travels in x minutes. what is the constant speed of the train in terms of hours?
The constant speed of the train is 108 miles per hour