50 * 3 = 150 and 150 * 3 = 450
So the answer is b 150
Correct Answer:
Option 3: <span>The quadratic function has two distinct real zeros.
The function is quadratic, therefore it can have only 2 zeros. The knowledge of x-intercepts is needed to determine the zeros, y-intercepts has nothing to do with the zeros of a function. The given function has 2 unique x-intercepts, so according to the fundamental theorem of algebra, this function has 2 distinct real roots as number of distinct real roots are equal to the number of x-intercepts. Therefore, option 3 is the correct answer. </span>
<u>Answer:</u>
Below!
<u>Explanation:</u>
Exponents are small numbers that defines how many times does the base needs to multiply itself. Two exponents can also be classified in words. 'Squared' defines a number multiplying itself two times. 'Cubed' defines a number multiplying itself three times. If there is a zero as the base's exponent, this means that the result will always be 1. Now, let's solve all the problems together.
- 2¹ = 2
- 3⁵ = 3 x 3 x 3 x 3 x 3 = 243
- 4³ = 4 x 4 x 4 = 64
- 6⁴ = 6 x 6 x 6 x 6 = 1256
- 7⁴ = 7 x 7 x 7 x 7 = 2401
- 1⁶ = 1 x 1 x 1 x 1 x 1 x 1 = 1
- 8² = 8 x 8 = 64
- 2³ = 2 x 2 x 2 = 8
- 4⁴ = 4 x 4 x 4 x 4 = 256
- 10³ = 10 x 10 x 10 = 1000
- 12² = 12 x 12 = 144
- 5⁴ = 5 x 5 x 5 x 5 = 625
- 6² = 6 x 6 = 36
- 3⁶ = 3 x 3 x 3 x 3 x 3 x 3 = 729
- 7³ = 7 x 7 x 7 = 343
- 2⁴ = 2 x 2 x 2 x 2 = 16
- 11⁰ = 1
- 4³ = 4 x 4 x 4 = 64
- 1¹² = 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 = 1
Hoped this helped!
Answer:
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Answer:
- f[1] = 3
- f[n] = 2·f[n-1] +4
- 108
Step-by-step explanation:
We observe that first differences of the given numbers are ...
10 -3 = 7
24 -10 = 14
52 -24 = 28
That is, each difference is 2× the previous one. This suggests an exponential relation that has a base of 2.
We notice that doubling a term doesn't give the next term, but gives a value that is 4 less than the next term. So, we can get the next term by doubling the previous one and adding 4.
Then our recursive relation is ...
f[1] = 3 . . . . the first term
f[n] = 2×f[n-1] +4 . . . . double the previous term and add 4
The next term is 2·52 +4 = 108.
