Answer:
33% chance
Step-by-step explanation:
there are 12 students total and there are two groups of students, boys and girls, 8 girls 4 boys so we take that and convert it to a fraction which would make 2/3 girls and 1/3 boys, so that would mean that boys have a 33% chance of being selected
Answer:
1. distance = sqrt( (7-7)^2+(2- -8)^2) = 10
2. check out desk (0,0 ) => distance = sqrt( (0- -9)^2+(0-0)^2) = 9
3. last corner ( -3, 4)
4. area = sqrt( (-10- -10)^2+(10-4)^2) x sqrt( (-3- -10)^2+(10-10)^2) = 6x7 =42
5. check desk (0,0), south direction = negative y axis => P_beginning (0,-20), P_end (0,-(20+25)) = (0,-45)
6. A(-2,-1) and B(4,-1) lie in y =-1. AB = sqrt( (-2- 4)^2+(-1- -1)^2) =6
=> area = 3.6x6 =21.6
=> peri = 2x(3.6+6) = 19.2
7. A(-5,4) and B(2,4), AB = sqrt( (-5- 2)^2+(4- -4)^2) = 7 => AB is base
=> p = peri = 7+ 8.3x2 = 23.6
=> area = sqrt[px(p-7)x(p-8.3)x(p-8.3)]
=sqrt[23.6x(23.6-7)x(23.6-8.3)x(23.6-8.3)] = 302.8
It's 28 pounds. 3,500/125 = 28 pounds.
There are 9 candies in total, with 5 being orange. Think of it. For the first grab, you have a 5/9 chance of it being orange flavored. Now there are 4 orange flavored candies, and 8 total candies in the bag. Grabbing a second candy, Billy has a 4/8 chance of grabbing an orange flavored candy. So your two fractions are...
5/9, 4/8
Can you combine these two fractions for a final answer?