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nadezda [96]
3 years ago
15

The temperature in a city was recorded over a ten-hour period. The graph below shows the relationship between the temperature an

d the number of hours.
Which statement best interprets information provided by the graph?
A. The temperature in the city increased for some time and decreased for some time.
B. The temperature remained constant for a while.
C. The temperature in the city increased throughout the period.
D. The temperature in the city increased at a constant rate for the entire time.

Mathematics
1 answer:
harkovskaia [24]3 years ago
5 0

Answer:

A

Step-by-step explanation:

From the graph, we can see that the <em>temperature increased initially</em>, then <em>started to decrease</em>. <u>All of these NOT in a constant rate, though</u>.

Roughly, the temperature was increasing from start till around 5.5 hours. Then on the temperature decreased.

So we can eliminate B, C, and D. That leaves us with correct answer as A.

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andrew11 [14]
I would say that it would be 119ft by 63ft
5 0
3 years ago
Find 5 points that satisfy the equation y= 12+2x
Goshia [24]
We start by finding the intercept of the line: what does y equal when x=0? and what does x equal when y=0?
• intercept in x
y = 12 + 2x
0 = 12 + 2x
-12 = 2x
-6 = x
• intercept in y
y = 12 + 2x
y = 12 + 2(0)
y = 12 + 0
y = 12
Now we find three more points giving y a value and finding x
y = 12 + 2x
2 = 12 + 2x
2-12 = 2x
-10 = 2x
-5 = x

y = 12 + 2x
6 = 12 + 2x
6 - 12 = 2x
-6 = 2x
-3 = x

y = 12 + 2x
14 = 12 + 2x
14 - 12 = 2x
2 = 2x
1 = x

Notice how I gave y even numbers as values since we would have to divide with 2 at the end.

Sol. {(-6,0)(0,12)(-5,2)(-3,6)(1,14)}
8 0
3 years ago
If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.
Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have S_1=3\times2^{1-1}+2(-1)^1=3-2=1, which agrees with the initial value <em>S</em>₁ = 1.

• Assume the closed form is correct for all <em>n</em> up to <em>n</em> = <em>k</em>. In particular, we assume

S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}

and

S_k=3\times2^{k-1}+2(-1)^k

We want to then use this assumption to show the closed form is correct for <em>n</em> = <em>k</em> + 1, or

S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}

From the given recurrence, we know

S_{k+1}=S_k+2S_{k-1}

so that

S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)

S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}

S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)

S_{k+1}=3\times2^k-2(-1)^k

S_{k+1}=3\times2^k+2(-1)(-1)^k

\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}

which is what we needed. QED

6 0
3 years ago
What is the diameter of the circumference of pi?
katen-ka-za [31]
When a circle's diameter is 1, its circumference is π.
4 0
3 years ago
Put 0.4 repeating into a fraction​
aliina [53]

Answer:

2/5=0.4=40%

Step-by-step explanation:

because if you divide 2/5 you'll get 0.4.  if you want to put that in a percent you'll multiply 0.4 and 100 and you should get 40%.

<em>HOPE THIS HELPS </em>

<em>yo girl trin.</em>

3 0
3 years ago
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