All categories

3 years ago

If anyone knows the answer for this question please help! 7th grade math.

Mathematics

1 answer:

madam [21]3 years ago

3 0

Answer:

47°

Step-by-step explanation:

(180 - 86) / 2 = measure of each congruent angle

94/2 = 47

You might be interested in

Which number is one-fourth of the way between 2.2 and 8.5?

icang [17]

8.5-2.2=6.3/2=3.15/2=1.575+2.2=3.775 which is your answer, 3.775

4 0

3 years ago

mr Lloyd's class raised 700$ this year to help manatees mrs Lloyd's class raised 636 for manatees how much more did mr Lloyds cl

yaroslaw [1]

Answer:

74 dollars

Step-by-step explanation:

When you see many more it means subtract

700

⁻636

074

74 dollars

6 0

4 years ago

The two-way relative frequency table shows the relative frequencies of late night workers and day workers who do or do not drink

MatroZZZ [7]

26.7 is your answer i hope that helps

5 0

3 years ago

Read 2 more answers

HELP PICS INCLUDED! WILL GIVE BRAINLIEST! SHOW WORK AND EXPLAIN

Naddik [55]

I assume you know about the dot product, and that for two vectors $\mathbf a$ and $\mathbf b$ , the angle between them $\theta$ satisfies

$\mathbf a\cdot\mathbf b=\|\mathbf a\|\|\mathbf b\|\cos\theta\iff\cos\theta=\dfrac{\mathbf a\cdot\mathbf b}{\|\mathbf a\|\|\mathbf b\|}$

Then the vectors are parallel if the angle between them is 0 or 180 degrees (0 or pi radians), which would make $\cos\theta=1$ or $\cos\theta=-1$ , respectively.

Part A)

$\vec v_1=\langle\sqrt3,1\rangle\implies\|\vec v_1\|=\sqrt{(\sqrt3)^2+1^2}=\sqrt4=2$

$\vec v_2=\langle-\sqrt3,-1\rangle=-\vec v_1\implies\|\vec v_2\|=\|\vec v_1\|=2$

$\vec v_1\cdot\vec v_2=(\sqrt3)(-\sqrt3)+(1)(-1)=-4$

Then the angle between $\vec v_1,\vec v_2$ is such that

$\cos\theta=\dfrac{-4}{(2)(2)}=-1\implies\theta=\pi\,\mathrm{rad}$

so these vectors are parallel ("antiparallel", more specifically, which means they are parallel but point in opposite directions).

Part B) involves the same computations:

$\vec u_1=\langle2,3\rangle\implies\|\vec u_1\|=\sqrt{2^2+3^2}=\sqrt{13}$

$\vec u_2$ has the same components but differing by sign and order, as $\vec u_1$ ; its magnitude remains the same, though:

$\vec u_2=\langle-3,-2\rangle\implies\|\vec u_2\|=\sqrt{(-3)^2+(-2)^2}=\sqrt{13}$

$\vec u_1\cdot\vec u_2=(2)(-3)+(3)(-2)=-12$

$\implies\cos\theta=\dfrac{-12}{(\sqrt{13})(\sqrt{13})}=-\dfrac{12}{13}\implies\theta=\cos^{-1}\left(-\dfrac{12}{13}\right)$

which is neither 0 nor pi, which means these vectors are not parallel.

4 0

4 years ago

Whats the answer ???? help dude

Natali [406]

Answer:

C. 44 °

Step-by-step explanation:

Angles on a straight line add up to 180 degrees.

180 - 88 = 92

Angles in a triangle add up to 180 degrees.

y + y + 92 = 180

y + y = 88

2y = 88

y = 88/2

y = 44

7 0

3 years ago

Read 2 more answers