Answer: B
Explanation:
Given that an object of mass 2 kg starts from rest and is allowed to slide down a frictionless incline so that its height changes by 20 m.
The parameters given from the question are:
Mass M = 2kg
Height h = 20m
Let g = 9.8m/s^2
At the bottom of the incline plane, the object will experience maximum kinetic energy.
From conservative of energy, maximum K.K.E = maximum P.E
Maximum P.E = mgh
Maximum P.E = 2 × 9.8 × 20 = 392 J
But
K.E = 1/2mv^2
Substitute the values of energy and mass into the formula
392 = 1/2 × 2 × V^2
V^2 = 392
V = sqrt( 392 )
V = 19.8 m/s
V = 20 m/s approximately
Answer:
Explanation:
3.4 m/s due North, -1.1 m/s due East
Mass (m)=55kg
acceleration (a)=9.81 m/s^2, this is the acceleration due to gravity.
initial velocity=0m/s. The skydiver doesn’t start with any speed because she is on the plane or helicopter.
final velocity=16m/s This is the velocity (speed) the skydiver reaches
The equation we use is KE=.5mv^2
Kinetic energy=.5 mass x velocity^2
KE=.5(55kg)(16m/s)^2
KE=.5(55kg)(256m/s)
KE=.5(14080J)
J=Joules
KE=7040J
Kinetic energy is 7040 Joules (J)
Hope this helps
Answer:
The maximum height the box will reach is 1.72 m
Explanation:
F = k·x
Where
F = Force of the spring
k = The spring constant = 300 N/m
x = Spring compression or stretch = 0.15 m
Therefore the force, F of the spring = 300 N/m×0.15 m = 45 N
Mass of box = 0.2 kg
Work, W, done by the spring = 
and the kinetic energy gained by the box is given by KE = 
Since work done by the spring = kinetic energy gained by the box we have
= therefore we have v = 
= 
= 
= 5.81 m/s
Therefore the maximum height is given by
v² = 2·g·h or h = 
= 
= 1.72 m
The absolute uncertainty in the volume of the cube is 0.06 m³.
We need to know about the uncertainty of measurement to solve this problem. The uncertainty of cube volume can be determined by
V = s³
|ΔV| = dV/ds x Δs
where V is volume, s is length, ΔV is uncertainty in the volume and Δs is the uncertainty of length.
From the question above, we know that
s = 1.00 m
Δs = 2% of s = 2/100 x 1 = 0.02 m
By using the uncertainty of volume formula, we get
|ΔV| = dV/ds x Δs
|ΔV| = d(s³)/ds x Δs
|ΔV| = 3s² x Δs
|ΔV| = 3. 1² x 0.02
|ΔV| = 0.06 m³
Hence, the uncertainty in the volume is 0.06 m³.
Find more on uncertainty at: brainly.com/question/1577893
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