Which one of these statements true about the moderator and the control rods a nuclear power station?

3. To calculate the _____ of a moving object, divide the displacement by the time interval in which the displacement occurred.

Alisiya [41]

<h3><u>Answer;</u></h3>

Average velocity

<h3><u>Explanation;</u></h3>

<em><u>Average Velocity of a moving body or an object is the ratio of total displacement covered to the time interval during which the displacement occurred.</u></em>

That is; Change in displacement divided by time.
The formula, therefore will be;

Average velocity = Displacement/ the time interval

Instantaneous Velocity on the other hand is the velocity of an object or a body at some instance.

8 0

3 years ago

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The Pinnacles and Neenach volcanics are 23.5 million-year-old andesite to rhyolite outcrops, on either side of the San Andreas F

Setler79 [48]

Answer:

v = 1.36 cm / y

Explanation:

For this exercise we must assume that the displacement of the plates is constant over time, so we will use the kinematic relationships for the uniform movement

v = d / t

We reduce the quantities to the SI system

d = 320 km (1000 m / 1km) (100 cm / 1 m)

d = 3.2 107 cm

let's calculate

v = 32.107 / 23.5 106

v = 1.36 cm / y

6 0

3 years ago

Charge q is 1 unit of distance away from the source charge S. Charge p is two times further away. The force exerted between S an

insens350 [35]

Answer : The correct option is, (d) 4 times

Solution :

According to the Coulomb's law, the electrostatic force of attraction or repulsion between two charges is directly proportional to the product of the charges and is inversely proportional to the square of the distance between the the charges.

Formula used :

$F=k_e\frac{q_1q_2}{r^2}$

where,

F = electrostatic force of attraction or repulsion

$k_e$ = Coulomb's constant

$q_1$ and $q_2$ are the charges

r = distance between two charges

First we have to calculate the force exerted between S and q when the distance between the charge is 1 unit and let us assumed that the charge be 'q'

$F_{sq}=k_e\frac{qq}{1^2}=k_e\times q^2$ ..........(1)

Now we have to calculate the force exerted between S and p when the distance between the charge is 2 unit at the same charge.

$F_{sp}=k_e\frac{qq}{2^2}=k_e\frac{q^2}{4}$ ...........(2)

Equation equation 1 and 2, we get

$\frac{F_{sq}}{F_{sp}}=\frac{1}{4}$

$F_{sq}=4\times F_{sp}$

Therefore, the force exerted between S and q is 4 times the force exerted between S and p.

5 0

3 years ago

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A stone is thrown from the top of a building with an initial velocity of 20 m/s downward. The top of the building is 60 m above

erastova [34]

Answer:

t = 2 s

Explanation:

In order to find the time taken by the stone to fall from the top of the building to the ground we can use 2nd equation of motion. 2nd equation of motion is as follows:

s = Vit + (0.5)gt²

where,

t = time = ?

Vi = Initial Velocity = 20 m/s

s = height of building = 60 m

g = 9.8 m/s²

Therefore,

60 m = (20 m/s)t + (0.5)(9.8 m/s²)t²

4.9t² + 20t - 60 = 0

solving this quadratic equation we get:

t = -6.1 s (OR) t = 2 s

Since, the time cannot be negative in magnitude.

Therefore,

6 0

3 years ago

Fig.3 shows three 10 g particles that have been glued to a rod of length L = 6 cm and negligible mass. The assembly can rotate a

Phoenix [80]

(a) The amount of work required to change the rotational rate is 0.0112 J.

(b) The decrease in the rotational inertia when the outermost particle is removed is 64.29%.

<h3>Moment of inertia of the rod</h3>

The moment of inertia of the rod from the axis of rotation is calculated as follows;

I = md² + m(2d)² + m(3d)²

where;

m is mass = 10 g = 0.01 kg
d = 3 equal division of the length

d = 6/3 = 2 cm = 0.02 m

I = md²(1 + 2² + 3²)

I = 14md²

I = 14(0.01)(0.02)²

I = 5.6 x 10⁻⁵ kg/m³

<h3>Work done to change the rotational rate</h3>

K.E = ¹/₂Iω²

K.E = ¹/₂(5.6 x 10⁻⁵)(60 - 40)²

K.E = ¹/₂(5.6 x 10⁻⁵)(20)²

K.E = 0.0112 J

<h3>Percentage decrease of rotational inertia when the outermost particle is removed</h3>

I₂ = md² + m(2d)²

I₂ = 5md²

ΔI = 14md² - 5md²

ΔI = 9md²

η = (ΔI/I) x 100%

η = (9md²/14md²) x 100%

η = 64.29 %

Learn more about rotational inertia here: brainly.com/question/14001220

#SPJ1

4 0

1 year ago