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4vir4ik [10]
3 years ago
6

I know the enthalpy of a reaction is 23kj/mol. Initially the reaction is taking place at 273 k. To what temperature do i need to

heat the reaction in order to double the equilibrium constant?

Physics
1 answer:
Vladimir79 [104]3 years ago
7 0

Answer:

293k

Explanation:

In this question, we are asked to calculate the temperature to which the reaction must be heated to double the equilibrium constant.

To find this value, we will need to use the Van’t Hoff equation.

Please check attachment for complete solution

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An object moves from the position +16m to the position +43m in 12s. What us the total displacement
NeX [460]

First method

initial distance = 16m

final distance= 43 m

total distance covered= final -initial

                                     =43m -16m

                                     =27m

Second method

Si= 16m

Sf =43 m

t= 12 s

first we will find V

V =  (Sf-Si)/ t

V =( 43- 16)/ 12

V = 27/12  ⇒ V= 9/4

V= distance / time

distance= V×time

distance = (9/4) ×12

distance =27

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3 years ago
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7 0
3 years ago
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nataly862011 [7]

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Electric field intensity is the force experienced by a test charge q in a electric field E.

7 0
3 years ago
Read 2 more answers
PLEASEEEEE!!!!
Fudgin [204]

Answer:

<h3>The answer is 2.0 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 100 g

volume = 50 mL

We have

density =  \frac{100}{50}  =  \frac{10}{5}  \\

We have the final answer as

<h3>2.0 g/mL</h3>

Hope this helps you

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D).  The boiling water is in contact with the egg,
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