Answer:
865.08 m
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 243 m/s
Height (h) of the cliff = 62 m
Horizontal distance (s) =?
Next, we shall determine the time taken for the cannon to get to the ground. This can be obtained as follow:
Height (h) of the cliff = 62 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
62 = ½ × 9.8 × t²
62 = 4.9 × t²
Divide both side by 4.9
t² = 62/4.9
Take the square root of both side.
t = √(62/4.9)
t = 3.56 s
Finally, we shall determine the horizontal distance travelled by the cannon ball as shown below:
Initial velocity (u) = 243 m/s
Time (t) = 3.56 s
Horizontal distance (s) =?
s = ut
s = 243 × 3.56 s
s = 865.08 m
Thus, the cannon ball will impact the ground 865.08 m from the base of the cliff.
Answer:
Right now I have three.
Explanation: Thanks for the points luv ^-^.
Answer:
, 
Explanation:
The acceleration of the plane can be determined by means of the kinematic equation that correspond to a Uniformly Accelerated Rectilinear Motion.
(1)
Where 
is the final velocity, 
is the initial velocity, 
is the acceleration and 
is the distance traveled.
Equation (1) can be rewritten in terms of ax:
(2)
Since the plane starts from rest, its initial velocity will be zero (
):
Replacing the values given in equation 2, it is gotten:
So, The acceleration of the plane is 
Now that the acceleration is known, the next equation can be used to find out the time:
(3)
Rewritten equation (3) in terms of t:
<u>Hence, the plane takes 26.92 seconds to reach its take-off speed.</u>
Answer:
Explanation:
The general consensus is that it's more “natural” to define distance (meter) and time (second) and as base units, and derive velocity a the ratio between them. ... The general consensus is that it's more “natural” to define distance (meter) and time (second) and as base units, and derive velocity a the ratio between them.
