Is this the full question that is stated?
Answer:
If the reindeer do not fight, there are 5!=120 ways to line them up in a straight line.
Out of these, Bloopin and Rudy are together in 4!=24 times. Similarly Rudy and Bloopin will be together 4!=24 times. So the number of ways they are not together is 120-24-24=72 ways.
Hope this helps. :)
Step-by-step explanation:
Spanish:
Si los renos no luchan, hay 5! = 120 formas de alinearlos en línea recta.
De estos, Bloopin y Rudy están juntos en 4! = 24 veces. De manera similar, Rudy y Bloopin estarán juntos 4! = 24 veces. Entonces, el número de formas en que no están juntas es 120-24-24 = 72 formas.
Espero que esto ayude :)
I think you count the squares in the middle or radius ?
<h2>1)</h2>
This must be true for some value of x, since we have a quantity squared yielding a positive number, and since the equation is of second degree,there must exist 2 real roots.
<h2>2)</h2>
Well he started off correct to the point of completing the square.
Answer: Your input has more than one equals sign.
Step-by-step explanation:
