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Paha777 [63]
3 years ago
5

The administration at Pierce College conducted a survey to determine the proportion of students who ride a bike to campus. Of th

e 125 students surveyed 6 ride a bike to campus. Which of the following is a reason the administration should not calculate a confidence interval to estimate the proportion of all students who ride a bike to campus? Check all that apply.
A. The sample needs to be random but we don’t know if it is.

B. The actual count of bike riders is too small.

C. The actual count of those who do not ride a bike to campus is too small.

D. n(p-hat) is not greater than 10.

E. n(1 minus p-hat) is not greater than 10.
Mathematics
1 answer:
8_murik_8 [283]3 years ago
6 0

Answer:

The correct option is (D).

Step-by-step explanation:

To construct the (1 - <em>α</em>)% confidence interval for population proportion the distribution of proportions must be approximated by the normal distribution.

A Normal approximation to binomial can be applied to approximate the distribution of proportion <em>p</em>, if the following conditions are satisfied:

  • n\hat p \geq 10
  • n ( 1 - \hat p) \geq 10

In this case <em>p</em> is defined as the proportions of students who ride a bike to campus.

A sample of <em>n</em> = 125 students are selected. Of these 125 students <em>X</em> = 6 ride a bike to campus.

Compute the sample proportion as follows:

\hat p=\frac{X}{n}=\frac{6}{125}=0.048

Check whether the conditions of Normal approximation are satisfied:

n\hat p =125\times 0.048=610

Since n\hat p, the Normal approximation to Binomial cannot be applied.

Thus, the confidence interval cannot be used to estimate the proportion of all students who ride a bike to campus.

Thus, the correct option is (D).

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x^{2}Answer:

(Explanation)

Step-by-step explanation:

Part A:

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This is what graph A should look like:

[Attached File]

Part B:

The graph of y = x^{2} - 2 will be translated 2 units down from the graph of y = x^{2}.

If you plug in 0 for x, you get a y-value of -2. The 2 is also not included with the x^{2}, which is why it doesn't translate right.

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[Attached File]

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The graph of y = 2x^{2} is a stretched version of the graph y = x^{2}. Numbers that are greater than 1 stretch and open up and numbers less than -1 stretch and open down.

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The graph of y = \frac{1}{2}x^{2} is a compressed version of the graph y = x^{2}. Numbers that are in-between 0 and 1, and -1 and 0 are compressed.

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If you have a cubic polynomial of the form y = ax^3 + bx^2 + cx + d and lets say it passes through the points (2,28), (-1, -5),
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Step-by-step explanation:

<u>Step 1:  Solve using the first point</u>

<em>(2, 28)</em>

28 = a(2)^3 + b(2)^2 + c(2) + d

28 = 8a + 4b + 2c + d

<u>Step 2:  Solve using the second point</u>

<em>(-1, -5)</em>

-5 = a(-1)^3 + b(-1)^2 + c(-1) + d

-5 = -a + b - c + d

<u>Step 3:  Solve using the third point</u>

<em>(4, 220)</em>

220 = a(4)^3 + b(4)^2 + c(4) + d

220 = 64a + 16b + 4c + d

<u>Step 4:  Solve using the fourth point</u>

<em>(-2, -20)</em>

-20 = a(-2)^3 + b(-2)^2 + c(-2) + d

-20 = -8a + 4b - 2c + d

<u>Step 5:  Combine the first and fourth equations</u>

<u />28 - 20 = 8a - 8a + 4b + 4b + 2c - 2c + d + d

8 = 8b + 2d

8 - 8b = 8b - 8b + 2d

(8 -8b)/2 = 2d/2

4 - 4b = d

<u>Step 6:  Solve for c in the second equation</u>

-5 + 5 = -a + b - c + d + 5

0 + c = -a + b - c + c + d + 5

c = -a + b + d + 5

<u>Step 7:  Substitute d with the stuff we got in step 5</u>

c = -a + b + (4 - 4b) + 5

c = -a + b + 4 - 4b + 5

c = -a - 3b + 9

<u>Step 8:  Substitute d and c into the first equation</u>

<u />28 = 8a + 4b + 2(-a - 3b + 9) + (4 - 4b)

28 = 8a + 4b - 2a - 6b + 18 + 4 - 4b

28 - 22 = 6a - 6b + 22 - 22

6 / 6 = (6a - 6b) / 6

1 + b = a - b + b

1 + b = a

<u>Step 9:  Substitute a, b, and c into the third equation</u>

220 = 64(1 + b) + 16b + 4(-(1 + b) - 3b + 9) + (4 - 4b)

220 = 64 + 64b + 16b + 4(-1 - b - 3b + 9) + 4 - 4b

220 - 100 = 60b + 100 - 100

120 / 60 = 60b / 60

2 = b

<u>Step 10:  Find a using b = 2</u>

a = b + 1

a = (2) + 1

a = 3

<u>Step 11:  Find c using a = 3 and b = 2</u>

c = -a - 3b + 9

c = -(3) - 3(2) + 9

c = -3 - 6 + 9

c = 0

<u>Step 12:  Find d using b = 2</u>

d = 4 - 4b

d = 4 - 4(2)

d = 4 - 8

d = -4

Answer:  a = 3, b = 2, c = 0,d = -4

6 0
3 years ago
Read 2 more answers
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