An equation relating the length that you measure l to the ship's proper length l0 is
l =l0/y. This is further explained below.
<h3>What is an equation relating the length that you measure l to the ship's proper length l0?</h3>
Generally, Any object's length in a moving frame will look shortened or contracted when seen in that direction. The Lorentz transformation may be used to determine the amount of contraction.
In conclusion, To use the Lorentz Lorentz transformation, the length Lo-x2 - may be determined if it is measured in the moving reference frame. Hence the Resultant l = l0/y.
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The result of 9 ∙ 10-⁵ divided by 3 ∙ 10-⁹ is 3 × 10⁴. Details about exponential functions can be found below.
<h3>How to calculate multiplication involving exponentiation?</h3>
Exponentiation is the process of calculating a power by multiplying together a number of equal factors, where the exponent specifies the number of factors to multiply.
According to this question, the following exponential function is given:
9 × 10-⁵ ÷ 3 × 10-⁹
9/3 × 10-⁵+⁹
3 × 10⁴
Therefore, the result of 9 ∙ 10-⁵ divided by 3 ∙ 10-⁹ is 3 × 10⁴.
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Answer:
a,)3.042s
b)4.173s
c)3.281s
Explanation:
For a some pendulum the period in seconds T can be calculated using below formula
T=2π√(L/G)
Where L = length of pendulum in meters
G = gravitational acceleration = 9.8 m/s²
Then we are told to calculate
(a) What is the period of small oscillations for this pendulum if it is located in an elevator accelerating upward at 3.00 m/s2?
Since oscillations for this pendulum is located in the elevator that is accelerating upward at 3.00 then
use G = 9.8 + 3.0 = 12.8 m/s²
Period T=2π√(L/G)
T= 2π√(3/12.8)
T=3.042s
b) (b) What is the period of small oscillations for this pendulum if it is located in an elevator accelerating downward at 3.00 m/s2?
G = 9.8 – 3.0 = 6.8 m/s²
T= 2π√(3/6.8)
T=4.173s
C)(c) What is the period of this pendulum if it is placed in a truck that is accelerating horizontally at 3.00 m/s2?
Net acceleration is
g'= √(g² + a²)
=√(9² + 3²)
Then period is
T=2π√(3/11)
T=3.281s
Answer:
The magnitude of the electric field equal to 2.40 N/C at 1.1537m from the wire.
Explanation:
using Guass law,
(guessing that a cylinder of radius r and length L around wire such that wire is at centre )
E. A = qin / e0
E ( 2πr L ) = (1.56 x 
x L) / (8.85 x 
)
E = (1.56 x ) / (2πr x 8.85 x )
so 2.40 = (1.54 x ) / (2πr x 8.85 x )
2.40 (6.284r) = 0.174 x 10²
15.0816r = 17.4
r = 1.1537m
Answer:
The velocity of the proton is 
Explanation:
The momentum of a particle is defined as the product of its mass by its velocity and we can calculate it using the following formula:
p=m*v Equation (1)
Where:
p: Is the momentum in kg*m/s
m: Is mass of the particle in kg
v: Is the velocity of the particle in m/s
Data known:
m= 1,6726 × 10^–27 kg : mass of the proton
p= 4.96 X 10^-19 kg.m/s.
We replace this data in the Equation (1):
Answer: The velocity of the proton is
