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IgorC [24]
3 years ago
7

Suppose you are in an elevator. As the elevator starts upward, its speed will increase. During this time when the elevator is mo

ving upward with increasing speed, your weight will be:_______.a) greater than your normal weight at rest.b) equal to your normal weight at rest.c) less than your normal weight at rest.
Physics
1 answer:
vova2212 [387]3 years ago
5 0

Answer: The answer is A.

Explanation:

Suppose you are in an elevator. As the elevator starts upward, its speed will increase. During this time when the elevator is moving upward with increasing speed, your weight will be greater than your normal weight at rest.

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After you cross the finish line, you slow down and come to a stop, breathing hard. It takes you 10 seconds to come to a stop. Wh
Otrada [13]

Acceleration = (change in speed) / (time for the change)

<em>Acceleration =  -- (speed as you crossed the finish line) / (10 seconds)</em>

4 0
2 years ago
Without steering, a car (mass 1501 kg) can travel with a certain speed around a banked frictionless corner angled at 25.0° to th
Rashid [163]

Answer:

30.30 m/s

Explanation:

mass of car, m = 1501 kg

angle of banking, θ = 25°

radius, r = 201 m

Let the speed is v.

The relation for the speed is given by

tan\theta =\frac{v^{2}}{rg}

tan25 =\frac{v^{2}}{201\times9.8}

v = 30.30 m/s

4 0
3 years ago
Express the vector R<br> B<br> in terms of A, B, C, and Ď, the edges of a<br> parallelogram.
Vadim26 [7]

Answer:

R=0.5B+0.5C+2A+D

Explanation:

By the triangular law of vector addition

vector R= vector B- vector D

As A,B,C,D are edges of the parallelogram,

A is parallel to D but opposite in direction.

Therefore

A = (-D);A//D;

2A=-2D

B is parallel to C and in same direction.

B//C\\B=C\\

0.5B=0.5C\\

R= B-D;\\R= 0.5B+0.5B-D;\\R=0.5B+0.5C-D;\\R=0.5B+0.5C-2D+D;\\R=0.5B+0.5C+2A+D;

7 0
2 years ago
Consider a turnbuckle that has been tightened until the tension in wire AD is 350 N. Draw the FBD that is required to determine
Mars2501 [29]

Answer:

yes

Explanation:

yes

6 0
2 years ago
The compound magnesium phosphate has the chemical formula Mg3(PO4)2. In this compound, phosphorous and oxygen act together as on
S_A_V [24]

The question is incomplete, the complete question is;

The compound magnesium phosphate has the chemical formula Mg3(PO4)2. In this compound, phosphorus and oxygen act together as one charged particle, which is connected to magnesium, the other charged particle. What does the 2 mean in the formula 5Mg3(PO4)2? A. There are two elements in magnesium phosphate. B. There are two molecules of magnesium phosphate. C. There are two magnesium ions in a molecule of magnesium phosphate. D. There are two phosphate ions in a molecule of magnesium phosphate.

Answer:

There are two phosphate ions in a molecule of magnesium phosphate.

Explanation:

The compound magnesium phosphate is an ionic compound. Ionic compounds always consists of two ions, a positive ion and a negative ion.

In this case, the positive ion is Mg^2+ while the negative ion is PO4^3-.

The subscript, 2 after the formula of the phosphate ion means that there are two phosphate ions in each formula unit of magnesium phosphate.

5 0
2 years ago
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