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Gnom [1K]
3 years ago
7

So My math teacher told me 2 do all of the ODD # This is 60 points!

Mathematics
1 answer:
weeeeeb [17]3 years ago
7 0
1)4x+14
2)x+9
3)x+21
4)x+15
5)9x+2
6)4x+26y
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Given mn, find the value of x.<br> 158
astra-53 [7]

Answer:

x=22

Step-by-step explanation:

8 0
3 years ago
A football is thrown from the top of the stands, 50 feet above the ground at an initial velocity of 62 ft/sec and at an angle of
Anvisha [2.4K]

a. i. The parametric equation for the horizontal movement is x = 43.84t

ii. The parametric equation for the vertical movement is y = 50 + 43.84t

b. the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

<h2>a. Parametric equations</h2>

A parametric equation is an equation that defines a set of quantities a functions of one or more independent variables called parameters.

<h3>i. Parametric equation for the horizontal movement</h3>

The parametric equation for the horizontal movement is x = 43.84t

Since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the horizontal component of the velocity is v' = vcosФ.

So, the horizontal distance the football moves in time, t is x = vcosФt

= vtcosФ

= 62tcos45°

= 62t × 0.7071

= 43.84t

So, the parametric equation for the horizontal movement is x = 43.84t

<h3>ii Parametric equation for the vertical movement</h3>

The parametric equation for the vertical movement is y = 50 + 43.84t

Also, since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the vertical component of the velocity is v" = vsinФ.

Since the football is initially at a height of h = 50 feet, the vertical distance the football moves in time, t relative to the ground is y = 50 + vsinФt

= 50 + vtcosФ

= 50 + 62tsin45°

= 50 + 62t × 0.7071

= 50 + 43.84t

<h3>b. Location of football at maximum height relative to starting point</h3>

The location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Since the football reaches maximum height at t = 1.37 s

The x coordinate of its location at maximum height is gotten by substituting t = 1.37 into x = 48.84t

So, x = 43.84t

x = 43.84 × 1.37

x = 60.0608

x ≅ 60.1 ft

The y coordinate of the football's location at maximum height relative to the ground is y = 50 + 48.84t

The y coordinate of the football's location at maximum height relative to the starting point is y - 50 = 48.84t

So,  y - 50 = 48.84t

y - 50 = 43.84 × 1.37

y - 50 = 60.0608

y - 50 ≅ 60.1 ft

So, the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Learn ore about parametric equations here:

brainly.com/question/8674159

5 0
2 years ago
47 1/2% in simplest form
Leya [2.2K]
The answer would be 47.5
5 0
4 years ago
Sam receives $50,000 for his monthly salary. If he pays $8,000 for electricity bill, $2,000bfor water bill and $10,000 for groce
sertanlavr [38]

Answer:

60%

Step-by-step explanation:

I HOPE THIS HELPS YOU OUT WITH YOUR QUESTION! PLZ LET ME KNOW IF IT DID! IT MAKES ME FEEL GOOD THAT SOMEONE APPRECIATES IT! ANYWAY, IF YOU HAVE A FEW MINUTES PLZ GOT TO MY PROFILE AND THANK MY ANSWERS (THE MORE THE MERRIER)

8 0
3 years ago
What two numbers add together to make -11
Paladinen [302]

Answer:

-6 and -5 (There are many more combinations of numbers that can equal to -11 but this is just one of the many possibilities.

Step-by-step explanation:

-6 and -5

See you can write it like this,

-6+ (-5)

= -6-5

=-11

5 0
3 years ago
Read 2 more answers
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