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grigory [225]
3 years ago
7

Helppp!! Malcolm is training for a marathon. He runs 3 miles in

Mathematics
1 answer:
Arlecino [84]3 years ago
7 0

Answer:

Malcolm would logically be running at 4.75 and since he is running at 3, it would be the lowest possible therefore its B

Step-by-step explanation:

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5.2 Two concentric circles have radii 7cm and 4cm respectively. PQ, a chord to the larger circle, is 13cm.
kodGreya [7K]

Two figures are known as similar figures if there the corresponding angles are equal and the corresponding sider is in ratio. The length of the smaller chord AB is 4 cm.

<h3>What are Similar Figures?</h3>

Two figures are known as similar figures if there the corresponding angles are equal and the corresponding sider is in ratio. It is denoted by the symbol "~".

The diagram for the given condition can be drawn as shown below. Therefore, the measure of the smaller chord AB can be found as shown below.

The two triangles, ΔOPQ and ΔOAB are similar. Therefore, for similar triangles, we can write,

\dfrac{PQ}{AB} = \dfrac{OQ}{OB}=\dfrac{PO}{AO}

Now, we can write further,

\dfrac{13}{AB} = \dfrac{7}{4}\\

AB = 7.43 cm

Hence, the length of the smaller chord AB is 4 cm.

Learn more about Similar Figures:

brainly.com/question/11315705

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2 years ago
What is greater 4.58 or 4.563
photoshop1234 [79]

Answer:

4.58 is greater then 4.563

3 0
3 years ago
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Math Vocabulary. Plese help.
grin007 [14]

Answer:

1. A Pythagorean triple

Step-by-step explanation:

4 0
3 years ago
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15,000 blue trout were released into the Meherrin River for a scientific study. The function, f(x) = 15,000( _ 9 8 ) x , represe
Airida [17]

Ask seri she helps with everything

8 0
3 years ago
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo
muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: {\displaystyle P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}}

Where \lambda is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}

Substitute the respective values in the above formula.

P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})

P(k > 2)= 1 - (0.44596)

P(k > 2)=0.55404

Hence, the required probability is 0.55404.

4 0
3 years ago
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