Start with
We observe that both fractions are not defined if 
. So, we will assume 
.
We multiply both numerator and denominator of the first fraction by 3 and we sum the two fractions:
We multiply both sides by 
:
We move everything to one side and solve the quadratic equation:
We check the solution:
which is true
the awser is (-2)(8 + 6) + (-3)
Answer:
Les trois nombres sont 5, 6 et 7.
Step-by-step explanation:
Soit x le premier nombre.
x + 1 sera le second et x + 2 sera le troisième.
On pose l'équation :
2x + 3(x + 1) = 4(x + 2)
2x + 3x + 3 = 4x + 8
5x - 4x = 8 - 3
x = 5
Answer:
y=-5,x=2
Step-by-step explanation:
3x+3y=-9________________eqn 1
3x-3y=21________________eqn 2
using elimination method
3x+3y=-9
-
3x-3y=21
subtract equation 2 from equation 1
0+6y=-30
6y=-30
y=-30/6
y=-5
substitute the value of y in equation 1
3x+3y=-9
3x+3(-5)=-9
3x-15=-9
3x=-9+15
3x=6
x=6/3
x=2
