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kobusy [5.1K]
3 years ago
7

You buy school clothes during a sale when everything in the store is 15% off. Which of the following could describe

Mathematics
1 answer:
Savatey [412]3 years ago
3 0

Answer:

(29.99 + 18.65 + 32.59) 0.85 = 0

(29.99 + 18.65 + 32.59) - 0.15(29.99 + 18.65 + 32.59) = 0

Step-by-step explanation:

The 15% off represents percentage discount. The relationship between percentage discount and total cost is given by the equation;

Actual cost - (Percentage discount) Actual cost = Total cost

The correct options are;

(29.99 + 18.65 + 32.59) 0.85 = 0

(29.99 + 18.65 + 32.59) - 0.15(29.99 + 18.65 + 32.59) = 0

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Suppose that x and y vary inversely, and x = 12 when y = 8 . Write the function that models the inverse variation.
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Answer:

y=\frac{96}{x}

Step-by-step explanation:

So when x and y, vary inversely, it means that the product of x and y will remain constant such that: xy=c. This means that the function can be defined as y=\frac{c}{x} by dividing both sides by x. In this case x=12, and y=8, this means the constant is equal to 12 * 8 which is 96. So we have the equation:  xy = 96, which can be defined as y=\frac{96}{x}

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Two sides of an isosceles triangle measure 3 inches and 7 inches. Which could be the length of the third side?
slamgirl [31]

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7

Step-by-step explanation:

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If you had 12 pieces of licorice to share equally among 5 people, how much licorice would each
pentagon [3]
12÷5=1.5 of licorice will each person get
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Find dy/dx if f(x) = (x + 8)^3x.
vlabodo [156]
This is quite a complex problem. I wrote out a really nice solution but I can't work out how to put it on the website as the app is very poorly made. Still, I'll just have to type it all in...

Okay so you need to use a technique called logarithmic differentiation. It seems quite unnatural to start with but the result is very impressive.

Let y = (x+8)^(3x)

Take the natural log of both sides:

ln(y) = ln((x+8)^(3x))

By laws of logarithms, this can be rearranged:

ln(y) = 3xln(x+8)

Next, differentiate both sides. By implicit differentiation:

d/dx(ln(y)) = 1/y dy/dx

The right hand side is harder to differentiate. Using the substitution u = 3x and v = ln(x+8):

d/dx(3xln(x+8)) = d/dx(uv)

du/dx = 3

Finding dv/dx is harder, and involves the chain rule. Let a = x+ 8:

v = ln(a)
da/dx = 1
dv/da = 1/a

By chain rule:

dv/dx = dv/da * da/dx = 1/a = 1/(x+8)

Finally, use the product rule:

d/dx(uv) = u * dv/dx + v * du/dx = 3x/(x+8) + 3ln(x+8)

This overall produces the equation:

1/y * dy/dx = 3x/(x+8) + 3ln(x+8)

We want to solve for dy/dx, achievable by multiplying both sides by y:

dy/dx = y(3x/(x+8) + 3ln(x+8))

Since we know y = (x+8)^(3x):

dy/dx = ((x+8)^(3x))(3x/(x+8) + 3ln(x+8))

Neatening this up a bit, we factorise out 3/(x+8):

dy/dx = (3(x+8)^(3x-1))(x + (x+8)ln(x+8))

Well wasn't that a marathon? It's a nightmare typing that in, I hope you can follow all the steps.

I hope this helped you :)
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