<h3>
Answer: A) 14</h3>
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Explanation:
Let's add point P at the location 0 on the number line.
The distance from L to P is 2 units. We can say LP = 2, ie segment LP is 2 units long.
Similarly, segment PN is 12 units long
Refer to the diagram below
The segments LP = 2 (red) and PN = 12 (blue) are then added to get the total distance from L to N. That total distance being LN = LP+PN = 2+12 = 14.
Point M is not used at all.
Answer:
120°
Step-by-step explanation:
All the angles of an equilateral triangle are equal, and hence have a measure of 60°.
∵ ∠AGF is a part of equilateral Δ AGF, m∠AGF = 60°.
∵ ∠FGE is a part of equilateral Δ AGF, m∠FGE = 60°.
Also note that ∠AGE = ∠AGF + ∠FGE.
⇒ m∠AGE = m∠AGF + m∠FGE
⇒ m∠AGE = 60° + 60°
= 120°.
Answer:
- x = -1/2(1 +√21) ≈ -2.79129
- x = -1/2(1 -√21) ≈ 1.79129
Step-by-step explanation:
We assume the middle term is supposed to be 4x.
We can remove a common factor of 4 to simplify this a bit.
x^2 +x -5 = 0
This is of the form
ax^2 +bx +c = 0
where a=1, b=1, c=-5.
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The <em>quadratic formula</em> gives the solutions as ...

Filling in the given coefficients, we have ...
x = (-1 ±√(1^2 -4·1·(-5)))/(2·1)
x = (-1±√21)/2
The solutions are x = -1/2(1 +√21) and -1/2(1 -√21).
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<em>If what you wrote is what you intend</em>, then the equation simplifies to 4x^2 -16 = 0.
Dividing by 4 and factoring the difference of squares gives ...
x^2 -4 = 0
(x -2)(x +2) = 0
These factors are zero (hence their product is 0) for the values x = 2 and x = -2.
The solutions are x=2 and x=-2.
80X3 PLUS 2x3 that is awnser
-5x(x+3)-7(x-3)/x^2-9= -5x^2-15x-7x+21/x^2-9= -5x^2-22x+21/x62-9