A(b)(-c), for a=7, b = -2, c= 15

Mathematics

2 answers:

Alexus [3.1K]3 years ago

8 0

A(b)(-c) = 7 (-2)(-15) = 7 (30) = 210. 210 is your answer. Hope this helped!

-Dominant- [34]3 years ago

4 0

You just have to plug in the numbers and solve
7(-2)(-15)
7(30)
210

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Kimane and a friend picked apples. Kimane picked 4 2/3 and his friend picked 5 5/6 pounds. About how many pound of apples do the

Gala2k [10]

Answer:

$9\dfrac{1}{2}$

Step-by-step explanation:

To find many more pounds of apples Kimane and his friend needs to get, we first need to find out how many pounds of apples they picked together.

Kimane = $4\dfrac{2}{3}$

Friend = $5\dfrac{5}{6}$

We add them together to find out how many pounds of apples they currently have.

Total Pounds = $4\dfrac{2}{3}+5\dfrac{5}{6}$

Just to make the equation clearer, we separate the whole numbers from the fractions.

$=4+5+\dfrac{2}{3}+\dfrac{5}{6}$

$=9+\dfrac{2}{3}+\dfrac{5}{6}$

Now since we cannot add the 2 fractions directly since they have different denominators, we need to convert the $/dfrac{2}{3}$ into a fraction with the same denominator.

We multiply both the numerator and denominator by 2 to have the same denominator.

$\dfrac{2*2}{3*2}=\dfrac{4}{6}$

So now we have:

$=9+\dfrac{4}{6}+\dfrac{5}{6}$

$=9+\dfrac{9}{6}or1\dfrac{1}{2}$

$Total Pounds = 10\dfrac{1}{2}$

Now that we know how many pounds Kimane and his friend collected, we simply subtract 20 and the total amount Kimane and his friend had already collected.

$20-10\dfrac{1}{2}$