You could easily change the 2 1/2 to a 2.5 and do 2.5-6=-3.5
Answer:
c= 1.16n
Step-by-step explanation:
j
Answer:
x1, x2 = 4.74 , -2.74
Step-by-step explanation:
To find the roots of a quadratic function we have to use the bhaskara formula
ax^2 + bx + c
x^2 - 2x - 13
a = 1 b = -2 c = -13
x1 = (-b + √ b^2 - 4ac)/2a
x2 =(-b - √ b^2 - 4ac)/2a
x1 = (2 + √ (2^2 - 4 * 1 * (-13)))/2 * 1
x1 = (2 + √ (4 + 52)) / 2
x1 = (2 + √ 56 ) / 2
x1 = (2 + 7.48) / 2
x1 = 9.48 / 2
x1 = 4.74
x2 = (2 - √ (2^2 - 4 * 1 * (-13)))/2 * 1
x2 = (2 - √ (4 + 52)) / 2
x2 = (2 - √ 56 ) / 2
x2 = (2 - 7.48) / 2
x2 = -5.48 / 2
x2 = -2.74
Your answer from smallest to largest is:
3/10
3/5
13/20
22/25
3M^2 + 11MN + 6N^2 = 3M^2 + 2MN + 9MN + 6N^2
= M(3M + 2N) + 3N(3M + 2N) = (3M + 2N)(M + 3N)
Answer: 3M^2 + 11MN + 6N^2 = (3M + 2N)(M + 3N)
