Find the slope of each line then tell what the slope represents

1 answer:

3 0

1. find slope
x=tickets sold
y=money made
slope=(y2-y1)/(x2-x1)
take any point
(5,23.75) and (10,47.50)
input (note, (x,y))
(47.50-23.75)/(10-5)=23.75/5=4.75
slope=4.75
y=mx+b
m=slope
b=yintercept
y=4.75x+b
input
47.5=4.75(10)+b
47.5=47.5+b
b=0

equation is y=4.75x
if ticket sold is 24 then x=24
y=4.75(24)
y=114
answer is $114

2. points
(0,56.00) and (3,45.5)
slope=(y2-y1)/(x2-x1)
slope=(45.5-56.00)/(3-0)=-3.5
y=-3.5x
slope=-3.5
logic it yourself
equation is
y=-3.5x+0
y intercept is when x=0 so when the start of it was or when time=0
x intercept is when y=0 is when he has no money left

1.a. rate of change=4.75
   b. $114

2. a.do this yourself, (desmos graphing calculator)
   b. slope=-3.5 (duh, means money goes down with time)
   c. equaiton is y=-3.5x+0, xint meanss when he has no money, y int means when time=0 or when it started

You might be interested in

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$