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uranmaximum [27]
3 years ago
6

Can someone answer this question and make sure they show working out. Will reward brainliest to the best answer.

Mathematics
1 answer:
wolverine [178]3 years ago
3 0

Answer:

8a²+8a+12b = 8a²+8a+12b

Step-by-step explanation:

first, expand the brackets

4a + 4a + 12a² + 8b + 4b - 4a²

then, collect like terms

8a + 8a² + 12b

then, rearrange

8a² + 8a + 12b

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f(x) = -3x - 1 when f(x) = -4
f(x) = -4 * -3 -1 = 12 - 1 = 11
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(2)+(-13)=<br>whats the answer?​
ziro4ka [17]

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- 11

Step-by-step explanation:

2 + ( - 13) \\ 2 - 13 =  - 11

5 0
3 years ago
What is 25.691 rounded to the greatest place
kvv77 [185]
The greatest place value is the tens spot which 2 is in the tens spot so we need to round up since 5 is next to the 2. The answer would be 30
4 0
2 years ago
HELP!!!! if you answer you get 20 points.
wolverine [178]

Answer:

Very last choice is the answer.

Step-by-step explanation:

Remark

The thing that is most important is that the horizontal line connect h and the radius is parallel to the cut of the sphere if it was placed right in the middle. That line swings around as though the center was a pivot.

Solution

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8 0
3 years ago
Uninhibited growth can be modeled by exponential functions other than​ A(t) ​=Upper A 0 e Superscript kt. For ​ example, if an i
laila [671]

The question is incomplete. Here is the complete question.

Uninhibited growth can be modeled by exponential functions other than A(t)=A_{0}e^{kt}. for example, if an initial population P₀ requires n units of time to triple, then the function P(t)=P_{0}(3)^{\frac{t}{n} } models the size of the population at time t. An insect population grows exponentially. Complete the parts a through d below.

a) If the population triples in 30 days, and 50 insects are present initially, write an exponential function of the form P(t)=P_{0}(3)^{\frac{t}{n} } that models the population.

b) What will the population be in 47 days?

c) When wil the population reach 750?

d) Express the model from part (a) in the form A(t)=A_{0}e^{kt}.

Answer: a) P(t)=50(3)^{\frac{t}{30} }

              b) P(t) = 280 insects

              c) t = 74 days

             d) A(t)=50e^{0.037t}

Step-by-step explanation:

a) n is time necessary to triple the population of insects, i.e., n = 30 and P₀ = 50. So, Exponential equation for growth is

P(t)=50(3)^{\frac{t}{30} }

b) In t = 47 days:

P(t)=50(3)^{\frac{t}{30} }

P(47)=50(3)^{\frac{47}{30} }

P(47)=50(3)^{1.567}

P(47) = 280

In 47 days, population of insects will be 280

c) P(t) = 750

750=50(3)^{\frac{t}{30} }

\frac{750}{50}=(3)^{\frac{t}{30} }

(3)^{\frac{t}{n} }=15

Using the property <u>Power</u> <u>Rule</u> of logarithm:

log(3)^{\frac{t}{30} }=log15

\frac{t}{30}log(3)=log15

t=\frac{log15}{log3} .30

t = 74

To reach a population of 750 insects, it will take 74 days

d) To express the population growth into the described form, determine the constant k, using the following:

A(t) = 3A₀ and t = 30

A(t)=A_{0}e^{kt}

3A_{0}=A_{0}e^{30k}

3=e^{30k}

Use Power Rule again:

ln3=ln(e^{30k})

ln3=30k

k=\frac{ln3}{30}

k = 0.037

Equation for exponential growth will be:

A(t)=50e^{0.037t}

3 0
3 years ago
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