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Klio2033 [76]
2 years ago
10

An automobile purchased for $39,000 is worth $1800 after 6 years. Assuming that the car's value depreciated steadily from year t

o year, what was it worth at the end of the third year?
The value 3 years after it was purchased is ? $_
Mathematics
1 answer:
ad-work [718]2 years ago
7 0

Answer:

3600

Step-by-step explanation:

1800+1800

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Uhhh I am struggling with this question algebra 1
Olin [163]

Answer:

-2x^2 +16x -8

Step-by-step explanation:

Oh s-

Like terms i guess Same variable you can substract. Remember you only substract from 1 number not from all.

-2x^2 stays the same as there is no like term

9x - (-7x)

-2 - (6)

-2x^2 + 9x+ 7x -2-6

-2x^2 +16x -8

4 0
3 years ago
What is m∠HLK? thanks
Katen [24]
The answer is 80°.

If there is a line segment in a triangle which cuts two sides in half or if there is a line segment between two midpoints of a triangle's sides, that line segment must be parallel to the remaining side.

In this case, point L is the midpoint of FH, and point K is the midpoint of HG. So, LK is parallel to FG.

When a line cuts two parallel lines, there are angle pairs which are equal. In the problem above, the line segment FH cuts KL and GF.

The angles KLH and GFH are what we called "Corresponding Angles" and they are equal.

So if HFG is 80°, HLK must be equal to 80°
3 0
3 years ago
Question1) Describe three scenarios that involve a real-world linear or exponential function. At least one must be exponential.
elixir [45]

Answer:

1) Let's suppose that you go in a straight line, in a car that moves at a constant speed of 80km/h.

Then the distance from your house (assuming that you start the drive in your house) can be modeled with a linear equation:

D(t) = 80km/h*t

where t is time in hours.

This will be a linear function.

2) Suppose that you have a population of some animal, that grows by 2% each month, and initially, there are 100 individuals of that animal.

Then the first month, the population is 100.

The second month the population increased by a 2%, then it will be:

100 + 100*0.02 = 100*(1.02)

The third month, the population will be 100*(1.02) + 0.2*100*(1.02) = 100*(1.02)^2.

and so on, this is an exponential relation, where the population as a function of the number of months, can be written as:

P(m) = 100*(1.02)^(m - 1)

3) Suppose that you have $100 saved, and each month you can save another $80, let's find a function that says the amount of money that you have saved as a function of the number of months. S(m)

The month number zero (before you started saving) you had $100 saved.

S(0) = $100.

One month after, you have saved $80 more, then you have:

S(1) = $100 + $80

Another month after, you have:

S(2) = $100 + $80 + $80 = $100 + 2*$80

And so on, you already can see the pattern, after m months, you will have:

S(m) = $100 + m*$80 saved.

5 0
2 years ago
A teacher gave her class two exams; 60% of the class passed the second exam, but only 48% of the class passed both exams. What p
Levart [38]
The answer is the last one - 48%
3 0
2 years ago
Help!! The table shows how many males and females
strojnjashka [21]

Answer:

frequency of females watching action movie is 99

total participants 479

joint relative frequency of females and action movie = 99/479

your answer is D: divide 99 by 479

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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