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Galina-37 [17]
4 years ago
15

20. Short Response A company is experimenting with two new boxes for packaging merchandise. Each box is a cube with the side len

gths shown. What is the ratio of the surface area of the smaller box to the surface area of the larger box?
Large box= 18in
Small box=12in
Mathematics
1 answer:
Anni [7]4 years ago
8 0
We are tasked to solve for the ratio of the two boxes. Boxes are cubes. We can use the formula in solving the surface area of the box as shown below:
Surface Area of Cube = 6a² where "a" is the length of the side.
For smaller box:
Area= 6(12)²=864
Area =864
For the larger box:
Area = 6(18)²
Area=1944

Then, the ratio is:
Area smaller box/Area larger box =864/1944
Ratio=4:9
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Use calculus to find the absolute maximum and minimum values of the function. (round all answers to three decimal places.) f(x)
Allisa [31]
Part A:

Given the function f(x)=x+2\cos(x), the absolute maximum or minimum occurs when f'(x)=0.

f'(x)=0 \\  \\ \Rightarrow1-2\sin{x}=0 \\  \\ \Rightarrow2\sin{x}=1 \\  \\ \Rightarrow\sin{x}= \frac{1}{2}  \\  \\ \Rightarrow x=\sin^{-1}{\frac{1}{2}}= \frac{\pi}{6}

Using the second derivative test,

f''(x)=-2cosx \\  \\ \Rightarrow f''\left( \frac{\pi}{6} \right)=-2\cos{\left( \frac{\pi}{6} \right)}=-1.732

Since the second derivative gives a negative number, the given function has a maximum point at x=\frac{\pi}{6}.

And the maximum point is given by:

f\left( \frac{\pi}{6} \right)=\frac{\pi}{6}+2\cos\left( \frac{\pi}{6} \right) \\  \\ =0.5236+2(0.8660)=0.5236+1.732 \\  \\ =\bold{2.256}

i.e. \left(\frac{\pi}{6},\ 2.256\right)



Part B:

Given the function f(x)=e^{-x}-e^{-2x}, the absolute maximum or minimum occurs when f'(x)=0.

f'(x)=0 \\ \\ \Rightarrow-e^{-x}+2e^{-2x}=0 \\ \\ \Rightarrow2e^{-2x}=e^{-x} \\ \\ \Rightarrow2e^{-x}=1 \\ \\ \Rightarrow e^{-x}=\frac{1}{2} \\  \\ \Rightarrow-x=\ln \frac{1}{2}=-0.6931 \\  \\ \Rightarrow x=0.6931

Using the second derivative test,

f''(x)=e^{-x}-4e^{-2x} \\ \\ \Rightarrow f''(0.6931)=e^{-0.6931}-4e^{-2(0.6931)} \\  \\ =0.5-4e^{-1.386}=0.5-4(0.25)=0.5-1 \\  \\ =-0.5

Since the second derivative gives a negative number, the given function has a maximum point at x=0.6931.

And the maximum point is given by:

f(0.6931)=e^{-0.6931}-e^{-2(0.6931)} \\  \\ =0.5-e^{-1.386}=0.5-0.25=\bold{0.25}

i.e. (0.693, 0.25)
3 0
3 years ago
The perimeter of the cover of a math textbook is 34 inches. if the width of the cover is 7 inches, what is the length of the cov
Sauron [17]
The length would be 10 inches.
to find perimeter, you add length+length+width+width.
since both widths and both lengths have to be the same, u add the width 2 times or 7+7=14.
next u subtract 14 from 34 or 34-14=20. 
since u still have 2 lengths that are equal, u divide 20 by 2 or 20/2=10

hope this helps! :)
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3 years ago
You install 540 feet of fencing along the perimeter of a rectangle yard. The width of the yard is 106 feet. Write and solve an e
In-s [12.5K]

Answer:

Step-by-step explanation:

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3 years ago
At sea level, the boiling point of water is 100°C. At an altitude of 7 km, the boiling point of water is 75.5°C. Find a linear f
enot [183]

Answer:

T(8.85\,km) = 69.025\,^{\textdegree}C

Step-by-step explanation:

Let assume that boiling point of water diminish linearly with the increase on altitude. Then, the expression needed is this first order polynomial:

T(z) = \frac{75.5\,^{\textdegree}C-100\,^{\textdegree}C}{7\,km-0\,km}\cdot z + 100\,^{\textdegree}C

The boiling point of water at a height of 8.85 km is:

T(8.85\,km) = 69.025\,^{\textdegree}C

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Find the value of each variables
BigorU [14]

Answer:

<em>X=11</em>

<em>y=22</em>

Step-by-step explanation:

tan60\frac{11\sqrt{3} }{x} \\\\\sqrt{3} =\frac{11\sqrt{3} }{x} \\\\x=\frac{11\sqrt{3} }{\sqrt{3} }

⇒x=11

Sib 60=\frac{11\sqrt{3} }{y} \\\\\frac{\sqrt{3} }{2} =\frac{11\sqrt{3} }{y} \\\\y=\frac{11\sqrt{3} }{\sqrt{\frac{3}{2} } }

⇒ y=22

<u>hope it helps....</u>

8 0
3 years ago
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