Help with #20 please
1 answer:
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Answer:
<u>Step-by-step explanation:</u>
cot is on the Unit Circle. When is cos =
and sin =
? In other words, where is the coordinate
on the Unit Circle?
It occurs at 60° = radians
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Answer: cot θ
<u>Step-by-step explanation:</u>
sec (90 - θ) * cos θ
= * cos θ
=
=
=
=
= cot θ
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Answer: BC = √5, AC = 2√5
<u>Step-by-step explanation:</u>
= 60°, which means ΔABC is a 30°-60°-90° triangle so we can use the side length formulas: x - x√3 - 2x.
∠C is the 60°. It matches to side AB so: AB = x√3 = √15 ⇒ x = √5
∠A is the 30°. It matches to side BC so: BC = x = √5
∠B is the 90°. It matches to side AC so: AC = 2x = 2(√5) = 2√5
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Answer: k = 4, RS = 12, QS = 28
<u>Step-by-step explanation:</u>
proportionality constant k can be found with =
= 4
→ 4 =
→ 4(3) = RS
→ 12 = RS
→ 4 =
→ 4(7) = QS
→ 28 = QS