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loris [4]
3 years ago
14

N(n+1)(n+2)(n+3)is a multiple of 4

Mathematics
2 answers:
RideAnS [48]3 years ago
3 0

Answer:

good evening,

You should notice that :

n=4K or n=4K+1 or n=4K+2 or n=4K+3

If n=4k so n(n+1)(n+2)(n+3)is a multiple of 4

If n=4K+1 so n+3 =4(k+1) so n(n+1)(n+2)(n+3)is a multiple of 4

If n=4K+2 so n+2 =4(k+1) so n(n+1)(n+2)(n+3)is a multiple of 4

If n=4K+3 so n+1=4(k+1) so n(n+1)(n+2)(n+3)is a multiple of 4

:)

Keith_Richards [23]3 years ago
3 0
Any multiple of 4 would work here its hard to explain i cant if u want but just try it & trust me
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The slope-intercept form of the equation of a line that passes through point (-2, -13) is y = 54 -3. What is the point slope
dangina [55]

Answer:

y+13=5(x+2)

Step-by-step explanation:

<u><em>The correct question is</em></u>

The slope-intercept form of the equation of a line that passes through point (-2, -13) is y = 5x -3. What is the point slope  form of the equation for this line?

we have

y=5x-3

This is the equation of the line in slope intercept form

where

the slope is m=5

the y-intercept is b=-3

Remember that

The equation of the line in point-slope form is equal to

y-y1=m(x-x1)

we have

m=5

point\ (-2,-13)

substitute

y-(-13)=5(x-(-2))

y+13=5(x+2)

3 0
4 years ago
Divide 6K2 - 15k-5 by 3k​
icang [17]

Answer:

Step-by-step explanation:

6k^2

------- = 2k; and:

 3k

-15k

------- = -5

 3k

-5 cannot be evenly divided by 3k, so there's a remainder instead.

6k^2 - 15k - 5

-------------------- = 2k -5 with remainder -5.

         3k

4 0
4 years ago
Read 2 more answers
If one point on a line is (-2,8) and the line’s slope is -3/2 find the y intercept
stellarik [79]

Answer:

The y intercept is 5

Step-by-step explanation:

The slope intercept form of an equation is

y = mx+b  where m is the slope and b is the y intercept

y = -3/2x+b

Substitute the point into the equation and solve for b

8 = -3/2(-2)+b

8 = 3+b

8-3 =b

5=b

The y intercept is 5

5 0
3 years ago
The solution to a quadric equation are x=2 and x=7. If k is a nonzero constant which of the following must be equal to the quadr
nikklg [1K]

Answer:

The quadratic equation form is x² - 9 x + 14  = 0            

Step-by-step explanation:

Given in the question as ,

The solution of quadratic equation are x = 2   and x = 7

The constant K is a non-zero number

Now , let the quadratic equation be , ax² + bx + c = 0

And  sum of roots = \frac{ - b}{a}

       product of roots = \frac{c}{a}

So, 2 + 7 = \frac{ - b}{a}

Or, 2 × 7 =  \frac{c}{a}

I.e \frac{ - b}{a}  = 9     ,     \frac{c}{a} = 14

Or,  b =  - 9 a           And c = 14 a

Put this value of b and c in standard form of quadratic equation

I.e ax² + bx + c = 0

Or, ax² - 9 ax + 14 a = 0

Or , a ( x² - 9 x + 14 ) = 0  

∴ a = 0   And  x² - 9 x + 14 = 0

Hence ,  The quadratic equation form is x² - 9 x + 14  = 0      Answer

7 0
3 years ago
my yearly income is 18,000. My medical insurance premium is 230 a month. Is my medical premium 9.66% less then yearly income?
JulijaS [17]
NO.....9.66% less than $18,000 is $16,261.20
230×12= $2,760
7 0
3 years ago
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