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4 years ago

Table of values y=x-3

1 answer:

monitta4 years ago

5 0

Y | 0 | 1 | 2 | 3 | 4 | 5 |.......................
x | -3 | -2 | -1 | 0 | 1 | 2 |.......................

This table continues to infinity

Please mark me as brainliest.

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Hlep plsi need bro im am stuck

Marta_Voda [28]

Answer:

its an enlargment

Step-by-step explanation: ur welcome :)

4 0

3 years ago

For one month Siera calculated her home town’s average high temperature in degrees Fahrenheit. She wants to convert that tempera

DaniilM [7]

Answer:

Option A) The temperature of F degrees Fahrenheit converted to degrees Celsius

Step-by-step explanation:

The formula to convert temperature from degrees Fahrenheit to degrees Celsius is:

$C(F)=\frac{5}{9}(F-32)$

If we have the measure of temperature in degrees Fahrenheit we can convert that temperature to degrees Celsius by substituting it in place of F. For example, if we want to convert 50 degrees Fahrenheit to degrees Celsius just replace F in the above formula by 50 and C(F) will give the equivalent temperature in degrees Celsius.

So, C(F) represents the temperature of F degrees Fahrenheit converted to degrees Celsius. Option A gives the correct answer.

5 0

3 years ago

Read 2 more answers

A garden table and a bench cost $657 combined. The garden table costs $93 less than the bench. What is the cost of the bench?

kompoz [17]

Answer:

im just trying to get points

Step-by-step explanation:

3 0

3 years ago

How do you simplify square root of -36 all divided by 2 into 3i and -3i?

posledela

Answer:+3i or -3i

Step-by-step explanation:

±√(-36)=+√(-36) or -√(-36)

+√(-1)×√(36) or -√(-1)×√(36) √(-1)=i

+i×6 or -i×6=+6i or -6i

Dividing by 2 we get

+6i/2 or -6i/2=+3i or -3i

5 0

3 years ago

A chemical substance has a decay rate of 6.9% per day. The rate of change of an amount N of the chemical is given by the equatio

GaryK [48]

Answer:

a) $N=N_0e^{-0.069t}$

b) $N=696.9$ grams

c) $t=10$ days

Step-by-step explanation:

We are going to use separation of variables to solve.

Get all your t's to one side and your N's to opposing side.

$\frac{dN}{dt}=-0.069N$

Multiply both sides by $dt$ :

$dN=-0.069N dt$

Divided both sides by $N$ :

$\frac{dN}{N}=-0.069 dt$

Integrate both sides:

$\ln|N|=-0.069t+C$

The equivalent exponential form is:

$e^{-0.069t+C}=N$

Using law of exponents you can write this as:

$e^{-0.069t}e^C=N$

$e^C$ is just a positive constant that I'm going to replace with K:

$e^{-0.069t}K=N$

Applying the symmetric property of equality:

$N=e^{-0.069t}K$

Applying the commutative property of multiplication:

$N=Ke^{-0.069t}$

K actually represents the initial amount of chemical substance since when plugging in 0 for t you get K for N, like so:

$N=Ke^{-0.069 \cdot 0}$

$N=Ke^{0}$

$N=K(1)$

$N=K$

We are given at time 0 the amount of chemical substance,N, is K. They want us to represent this value with $N_0$ instead. So the exponential equation is: