Answer:
Step-by-step explanation:
Given the function
y = (9x⁴ — 4x² + 6)⁴
We need to find the derivative of y with respect to x i.e. dy/dx.
So let u = 9x⁴—4x² + 6
Then y = u²,
Then, y is a function of u, y=f(u)
Also, u is a function of x, u = g(x)
In this case,
u = g(x) = 9x⁴—4x² + 6
So let differentiate this function y(x).
This is a function of a function
Then, we need to find u'(x)
u (x) = 9x⁴—4x² + 6
Then, u'(x) = 36x³ — 8x
Also we need to find y'(u)
Then, y = u²
y'(u) = 2u
Using function of a function formula
dy / dx = dy/du × du/dx
y'(x) = y'(u) × u'(x)
y'(x) = 2u × 36x³ — 8x
y'(x) = 2u(36x³ — 8x)
Since, u = 9x⁴—4x² + 6
Therefore,
y'(t) = 2(9x⁴—4x² + 6)(36x³ — 8x)
So,
dy/dx = 2(9x⁴—4x² + 6)(36x³ — 8x)
dy/dx = (18x⁴—8x² + 12)(36x³ — 8x)
The discount was 35%
to find that i did 32.5 / 50 and found 0.65 which means thats 32.5 is 65% of 50, but 17.5 was taken off and 17.5 is 35% of 50.
Answer:
.
Step-by-step explanation:
Dilate a point 
by a scale factor of 
with 
as the center, and the resultant point would be at 
.
In this question:
Point to dilate: 
.
Scale factor: 
.
Center of dilation: 
.
The resultant point would be:
, which simplifies to .
