The equation of parabola becomes y = -2/25(x-3)^2 + 4.
According to the statement
we have given a graph and from this graph we have to find the equation of parabola in the general form.
So,
we know that the equation of parabola in general form is
y = a(x-h)^2 +k - (1)
From the graph we have:
a point on the graph is (x,y) = (-2,2)
the vertex of the graph is (h,k) = (3,4)
Now, substitute these values in the equation number (1)
Then
y = a(x-h)^2 +k
2 = a(-2-3)^2 +4
2 = a(-5)^2 +4
2 = a(25) +4
25a = -2
a = -2/25.
Now put a = -2/25 and (h,k) = (3,4) in the equation(1).
Then
the equation of parabola becomes y = -2/25(x-3)^2 + 4
So, The equation of parabola becomes y = -2/25(x-3)^2 + 4.
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I'm not sure but I think it is
4.48×10 10 <---this to is an exponent
It is false that the midpoint is in quadrant IV
<h3>How to determine the midpoint location?</h3>
The endpoints are given as:
S (1,4) and T (5,2
The midpoint is
(x, y) = 0.5 *(x1 + x2, y1 + y2)
So, we have:
(x, y) = 0.5 *(1 + 5, 4 + 2)
Evaluate the expression
(x, y) = (3, 3)
The point (3, 3) is located in the first quadrant
Hence, it is false that the midpoint is in quadrant IV
Read more about quadrants at:
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Answer:
21/7= 3
Step-by-step explanation:
Answer:
d. The variance is 9.56 and the standard deviation is 3.09.
Step-by-step explanation:
From the above question, we are given the following data set.
3, 7, 8, 8, 8, 9, 10, 10, 13, 14
a) Mean = 3 + 7 + 8 + 8 + 8 + 9 + 10 + 10 + 13 + 14/ 10
= 90/10
= 9
b) Variance
The formula for sample Variance = (Mean - x)²/ n - 1
Mean = 9
n = 10
Sample Variance =
(3 - 9)² + (7 - 9)² + (8 - 9)² + (8 - 9)² + (8 - 9)² + (9 - 9)² + (10 - 9)² + (10 - 9)² + (13 - 9)² + (14 - 9)² / 10 - 1
= 36 + 4 + 1 + 1 + 1 + 0 + 1 + 1 + 16 + 25/9
= 86/9
= 9.555555556
≈ Approximately 9.56
Variance = 9.56
Sample Standard deviation = √Sample Variance
= √9.56
= 3.0919249667
≈ Approximately 3.09
