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Svetach [21]
3 years ago
14

Find the value of the variables. Diagram above. Tysm please help very urgent!

Mathematics
1 answer:
serious [3.7K]3 years ago
8 0

Answer:

If you look at the different triangles in the star they give you two angles....

all of the points in a triangle would be equal and you just subtract  24 from 105

x is 24 and y is 81

Step-by-step explanation:

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Which fractions are equivalent to 8/20 ?
Nadusha1986 [10]

Answer:

2/5. 4/10. 6/15. 8/20. 10/25. 12/30

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A power plant discharges water into a river. Regulators determine that as long as the mean temperature of the discharged water i
nlexa [21]

Answer:

(A) Type I error in the context of this problem is chances of regulators believing that the mean temperature of the discharged water is more than 150°F but in actual the mean temperature of the discharged water was 150°F.

(B) Type II error in the context of this problem is chances of regulators believing that the mean temperature of the discharged water is no more than 150°F but in actual the mean temperature of the discharged water was more than 150°F.

(C) An environmental group will consider the Type II error more serious.

Step-by-step explanation:

We are given that a power plant discharges water into a river. Regulators determine that as long as the mean temperature of the discharged water is no more than 150°F, there will be no negative effects on the river’s ecosystem.

We are also given with the following hypothesis;

Null Hypothesis, H_0 : \mu = 150°F

Alternate Hypothesis, H_a : \mu > 150°F

(A) <u><em>Type I error</em></u><em> states that Probability of rejecting null hypothesis given the fact that null hypothesis was true or in other words Probability of rejecting a true hypothesis.</em>

So, Type I error in the context of this problem is chances of regulators believing that the mean temperature of the discharged water is more than 150°F but in actual the mean temperature of the discharged water was 150°F.

(B) <u><em>Type II error </em></u><em>states that Probability of accepting null hypothesis given the fact that null hypothesis was false or in other words Probability of accepting a false hypothesis.</em>

So, Type II error in the context of this problem is chances of regulators believing that the mean temperature of the discharged water is no more than 150°F but in actual the mean temperature of the discharged water was more than 150°F.

(C) An environmental group will consider the Type II error more serious because by committing Type II error they believe that the mean temperature of the discharged water is no more than 150°F and they assume that there is no negative effects on the river’s ecosystem but in reality that the mean temperature of the discharged water was more than 150°F and it is producing negative effects on the river’s ecosystem.

8 0
3 years ago
The point slope form of a line that has a slope of -2 and passes through point (5,-2) is shown below.
Likurg_2 [28]
Insert the point, (5,-2) with the slope of the line to figure out the equation. You can either use point-slope form, or plug it for for slope-intercept form.

Slope-intercept form:
-2 = -2(5) + b
-2 = -10 + b
Add 10 on both sides
8 = b

Thus,

y = -2x + 8

Answer is B
4 0
2 years ago
A pair of shorts are £15 in a 40%. What was the non-sale price
lana66690 [7]

Answer:

£10.71

Step-by-step explanation:

Given the original price including discount od shorts = £15

Percent discount = 40%

Original price = x

Using the expression to calculate x

x + (40%of x) = 15

x +0.4x = 15

1.4x = 15

x = 15/1.4

x = £10.71

Hence the non sale price is £10.71

4 0
3 years ago
A ship leaves port on a bearing of 34.0 and travels 10.4 mi. the ship then turns due east and travels 4.6mi. how far is the ship
Natasha2012 [34]
A bearing of 34° corresponds to corresponding angle of θ=90-34=56°
The (x,y) values for the position of the ship after completing its first heading are:
x=(10.4cos 56)
y=(10.4sin56)

The trigonometric angle for θ=90-90=0
The (x,y) values for the postion of the ship after completing the second bearing is:
x=(10.4 cos56)+(4.6cos0)≈10.4 mi
y=(10.4sin56)+(4.6sin0)≈8.6mi

the distance from the port will therefore be:
d=√(10.4²+8.6²)≈13.5 miles

It trigonometric angles is:
θ=arctan(y/x)
θ=arctan(8.6/10.4)
θ≈39.6°
Thus the bearing angle is:
90-39.6=50.4°
6 0
3 years ago
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