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sergejj [24]
3 years ago
12

The average rate of change of f from 2 to 3

Mathematics
1 answer:
ella [17]3 years ago
3 0

For a function of f, the average rate of change can be found as follows:


ARC=\frac{f(x_{2})-f(x_{1})}{x_{2}-x_{1}}


So, this problem asks for the Average Rate of Change of f from x_{1}=2 to x_{2}=3. In this way, we need to find f(x_{1}) \ and \ f(x_{2}). As you can see above, we have the graph of f(x), so we can find these values. Thus, from the graph:


f(x_{1})=4 \\ f(x_{2})=1


Therefore:


ARC=\frac{1-4}{3-2} \\ \\ \therefore \boxed{ARC=-3}

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Find the total volume. Please show your work.​
elena-s [515]

Answer:

Step-by-step explanation:

You have a half sphere and a cylinder.

Trick question! Note that the diameter of the cylinder is in meters, while the height is given in centimeters.

For cylinder:

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For sphere:

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Total volume = 1.5π + 250π/3 ≅ 266.5 m³

4 0
3 years ago
Help me simplify this, please!!
OlgaM077 [116]
- \sqrt[3]{2 x^{4} y^{2}  } *3 \sqrt[3]{20 x^{5}y } =-3  \sqrt[3]{2 x^{4} y^{2}20 x^{5}y} =  \\ \\ =-3 \sqrt[3]{40 x^{9}  y^{3} } =-3 \sqrt[3]{2 ^{3}*5* x^{9}  y^{3}  } = \\  \\ =-3*2 ^{ \frac{3}{3} } * x^{ \frac{9}{3} } * y^{ \frac{3}{3} }  \sqrt[3]{5} =-6 x^{3} y \sqrt[3]{5}
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6 0
3 years ago
Evaluate the expression x+5 for when x=2
aksik [14]
Wouldnt that be 2+5 ?? if x is 2 it’s simple, just add them and you get 7.
6 0
3 years ago
Read 2 more answers
(3 3/4) divided by (-2 1/2)
GalinKa [24]

Answer:

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3 0
3 years ago
The given line passes through the points (0, −3) and (2, 3).
Alex Ar [27]
Well, parallel lines have the same exact slope, so hmmm what's the slope of the one that runs through <span>(0, −3) and (2, 3)?

</span>\bf \begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ 0 &,& -3~) &#10;%  (c,d)&#10;&&(~ 2 &,& 3~)&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope =  m\implies &#10;\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{3-(-3)}{2-0}\implies \cfrac{3+3}{2-0}\implies 3
<span>
so, we're really looking for a line whose slope is 3, and runs through -1, -1

</span>\bf \begin{array}{ccccccccc}&#10;&&x_1&&y_1\\&#10;%  (a,b)&#10;&&(~ -1 &,& -1~)&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope =  m\implies 3&#10;\\\\\\&#10;% point-slope intercept&#10;\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-1)=3[x-(-1)]&#10;\\\\\\&#10;y+1=3(x+1)<span>
</span>
8 0
3 years ago
Read 2 more answers
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