What is the equation of the line that passes through the point (4, -7) and has a

Mathematics

1 answer:

otez555 [7]3 years ago

8 0

Answer:

I think that some information is missing? what is the slope?

If you are trying to say that there is NO SLOPE then the

answer is " x = 4 "

Step-by-step explanation:

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Match the solution set given in inequality with the best solution set given in interval notation

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There you go

I hope this help you

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Rectangle is 5 feet wide and 11 feet long. What is the perimeter

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Just add all side

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Read 2 more answers

What is 3.47 correct to 2 decimal places what is 8.132 correct to 3 decimal places

Olenka [21]

If I'm understanding the question they should be those. If you want to go left then the would be

Left
0.00347
0.008132

Right
347.
8,132.

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3 years ago

Do you compare a negative decimal to a positive decimal?

Anika [276]

Answer:

Positive: Decimals are a part of a whole just like fractions are a part of a whole. Therefore, a positive decimal is always greater than a negative decimal.

Negative: When you have two negative decimals, the one closer to zero is always greater. The farther a negative decimal is from zero, the smaller its value.

All of it put together (same text as above):

Decimals are a part of a whole just like fractions are a part of a whole. Therefore, a positive decimal is ALWAYS greater than a negative decimal. When you have two negative decimals, the one closer to zero is always greater. The farther a negative decimal is from zero, the smaller its value.

5 0

3 years ago

How to solve this question

VMariaS [17]

The variance method is as follows.

-Sum the squares of the values in data set, and then divide by the number of values in data set
- From that, subtract the square of the mean (add all values and divide by number of values in the data set)

Our variance is

 $\displaystyle\sigma^2 = \frac{2^2 + 5^2 + m^2}{3} - \left(\frac{2 + 5 + m}{3}\right)^2$

Since variance has to be 14, we set $\sigma^2 = 14$ and solve for m

$14= \frac{4 + 25 + m^2}{3} - \left(\frac{7 + m}{3}\right)^2\ \Rightarrow \\ \\
14 = \frac{29}{3} + \frac{1}{3}m^2 - \frac{1}{9}(7+m)^2 \\ \\
14 = \frac{29}{3}+ \frac{1}{3}m^2 - \frac{1}{9}(49 + 14m + m^2) \\ \\
14 = \frac{29}{3}+ \frac{1}{3}m^2 - \frac{49}{9}- \frac{14}{9}m- \frac{1}{9}m^2 \\ \\
0 = \frac{-88}{9} -\frac{14}{9}m + \frac{2}{9}m^2
$

quadratic formula

$m = \displaystyle\frac{-b \pm \sqrt{b^2 -4ac}}{2a} \\
m = \frac{-(-\frac{14}{9}) \pm \sqrt{\left(-\frac{14}{9}\right)^2 - 4(2/9)(-88/9)} }{2(2/9)} \\
m = \frac{\frac{14}{9} \pm \sqrt{ \frac{196}{81} + \frac{704}{81} } }{\frac{4}{9} } \\
m = \frac{\frac{14}{9} \pm \sqrt{ \frac{900}{81} } }{\frac{4}{9} } \\
m = \frac{\frac{14}{9} \pm \sqrt{ \frac{100}{9} } }{\frac{4}{9} } \\
m = \frac{\frac{14}{9} \pm \frac{10}{3} }{\frac{4}{9} } \\
m = 11, -4$

-4 doesnt' work as it is not a positive integer

m = 11

5 0

3 years ago